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marusya05 [52]
3 years ago
15

The vertices of figure KLMN are

Mathematics
1 answer:
Molodets [167]3 years ago
8 0

Answer:

N'(9, -1)

Step-by-step explanation:

N(-5, -1)

Point N has x-coordinate -5. It is 5 units to the left of the the y-axis, and another 2 units away from the line x = 2. That makes point N 7 units to the left of the line x = 2. 7 units to the right of line x = 2, the x-coordinate is 2 + 7 = 9.

Answer: N'(9, -1)

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How many solutions does the equation y=3x have?
Butoxors [25]

Answer:

1 solution

Step-by-step explanation:

If you were to graph this line it would be a straight line so there is 1 solution.

y=3x

x=y/3

7 0
2 years ago
Please help will mark branliest
Citrus2011 [14]

Answer:

RS = 17

Step-by-step explanation:

QS = 62

RS = ?

QR = 45

QS - QR = RS

62 - 45 = 17

Thus RS = 17

3 0
3 years ago
THE WORLD'S MOST HARDEST QUESTION<br><br> what is 9484 * 6584 in scientific notation
liq [111]
The answer is 62,442,656

scientific notation its 6.2442656 * 10 to the 7th power

word form its 62 million 442 thousand 656
3 0
3 years ago
Read 2 more answers
Can you please help me on this one, I'm stuck =(<br>​
natka813 [3]

Answer:

wow. this is a hard one. i would choose that c would be 2 and d would be 6.

Step-by-step explanation:

well, what i did was first went ahead and reflected the x-axis. then, i made the first translation, c. then, i went ahead and found out the translation of d. YOU COUNT THE SQUARES.

8 0
3 years ago
A 10-foot ladder is leaning against a vertical wall. If the bottom of the ladder is being pulled away from the wall at the rate
Alex777 [14]

Answer:

The area is changing at 15.75 square feet per second.

Step-by-step explanation:

The triangle between the wall, the ground, and the ladder has the following dimensions:

H: is the length of the ladder (hypotenuse) = 10 ft

B: is the distance between the wall and the ladder (base) = 6 ft

L: the length of the wall (height of the triangle) =?

dB/dt = is the variation of the base of the triangle = 9 ft/s        

First, we need to find the other side of the triangle:  

H^{2} = B^{2} + L^{2}

L = \sqrt{H^{2} - B^{2}} = \sqrt{(10)^{2} - B^{2}} = \sqrt{100 - B^{2}}

Now, the area (A) of the triangle is:            

A = \frac{BL}{2}  

Hence, the rate of change of the area is given by:

\frac{dA}{dt} = \frac{1}{2}[L*\frac{dB}{dt} + B\frac{dL}{dt}]      

\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - B^{2}}*\frac{dB}{dt} + B\frac{d(\sqrt{100 - B^{2}})}{dt}]        

\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - B^{2}}*\frac{dB}{dt} - \frac{B^{2}}{(\sqrt{100 - B^{2}})}*\frac{dB}{dt}]  

\frac{dA}{dt} = \frac{1}{2}[\sqrt{100 - 6^{2}}*9 - \frac{6^{2}}{\sqrt{100 - 6^{2}}}*9]      

\frac{dA}{dt} = 15.75 ft^{2}/s  

     

Therefore, the area is changing at 15.75 square feet per second.

I hope it helps you!                                    

5 0
3 years ago
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