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marin [14]
3 years ago
7

What are the possible values of x and y for two distinct points, (5,-2) and (x, y), to represent a function?

Mathematics
1 answer:
gayaneshka [121]3 years ago
3 0
The answer could be (6,3) or ( -3,8)
You might be interested in
The tensile strength of a metal part is normally distributed with mean 40 pounds and standard deviation 5 pounds. If 50,000 part
nalin [4]

Answer:

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

7933 parts

b) How many would have a tensile strength in excess of 48 pounds?

2739.95 parts

Step-by-step explanation:

The formula for calculating a z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

z = (x-μ)/σ

x = 35 μ = 40 , σ = 5

z = 35 - 40/5

= -5/-5

= -1

Determining the Probability value from Z-Table:

P(x<35) = 0.15866

Converting to percentage = 15.866%

We are asked how many will fail to meet this specification

We have 50,000 parts

Hence,

15.866% of 50,000 parts will fail to meet the specification

= 15.866% of 50,000

= 7933 parts

Therefore, 7933 parts will fail to meet the specifications.

b) How many would have a tensile strength in excess of 48 pounds?

z = (x-μ)/σ

x = 48 μ = 40 , σ = 5

z = 48 - 40/5

z = 8/5

z = 1.6

P-value from Z-Table:

P(x<48) = 0.9452

P(x>48) = 1 - P(x<48)

1 - 0.9452

= 0.054799

Converting to percentage

= 5.4799%

Therefore, 5.4799% will have an excess of (or will be greater than) 48 pounds

We are asked, how many would have a tensile strength in excess of 48 pounds?

This would be 5.4799% of 50,000 parts

= 5.4799% × 50,000

= 2739.95

Therefore, 2739.95 parts will have a tensile strength excess of 48 pounds

4 0
3 years ago
What is the result of 2 divided by StartFraction 4 Over 10 EndFraction? A number line going from 0 to 2. One-fifth Four-fifths 5
mixer [17]

5

You just divide it normally

8 0
3 years ago
Read 2 more answers
The area of room in a dollhouse is 1248 sq in. the width of the room is 8 in. how long is the room?
Tanzania [10]
The length of the room is 156 sq in
6 0
3 years ago
The following data points represent the yearly salaries of high school cheerleading coaches in Dakota county (in thousands of do
jenyasd209 [6]

Answer:

5.6 thousand

Step-by-step explanation:

To find the mean absolute deviation (MAD), first find the mean (or average).

μ = (41 + 38 + 36 + 57 + 43) / 5

μ = 43

Next, subtract the mean from each value and take the absolute value.

|41 − 43| = 2

|38 − 43| = 5

|36 − 43| = 7

|57 − 43| = 14

|43 − 43| = 0

Sum the results and divide by the number of animals.

MAD = (2 + 5 + 7 + 14 + 0) / 5

MAD = 5.6

5 0
3 years ago
I'm gonna cry I don't get this​
snow_tiger [21]

Answer:

d=14

Step-by-step explanation:

Divide both sides by the numeric factor on the left side, then solve.

so the answer is d=14

6 0
2 years ago
Read 2 more answers
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