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babymother [125]

3 years ago

13

The angle turns through 1/6 of the circle. What is the measure of the

1 answer:

s344n2d4d5 [400]3 years ago

7 0

Answer:

60

Step-by-step explanation:

A circle is 360 degrees. If we rotate through 1/6 of the circle

360 *1/6 = 60

We rotate through 60 degrees

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Solve the equation using the quadratic formula : x^2-10x+25=18

Sever21 [200]

$x^2-10x+25=18 \\ \\x^2-10x+25-18 = 0\\ \\ x^2-10x+ 7 =0 \\ \\a=1 , b = -10 , c= 7 \\ \\ \Delta = b^{2}-4ac = (-10)^{2}-4*1*7=100-28 = 72 \\ \\\sqrt{\Delta }=\sqrt{72}= \sqrt{2*36} =\sqrt{36}*\sqrt{2} =6\sqrt{2}$

$x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{10- 6\sqrt{2}}{2}=\frac{2(5-3\sqrt{2})}{2}= 5-3\sqrt{2}\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{10+ 6\sqrt{2}}{2}=\frac{2(5+3\sqrt{2})}{2}= 5+3\sqrt{2}$

$Answer : \ x= 5-3\sqrt{2} \ \ or \ \ x = 5+3\sqrt{2}$

8 0

3 years ago

Please help thank you very much

Tom [10]

Answer:

$4x^{2} -6x$

Step-by-step explanation:

3 0

3 years ago

Two identical rubber balls are dropped from different heights. Ball 1 is dropped from a height of 109 feet, and ball 2 is droppe

Natalija [7]

Answer: 5.22 seconds

<u>Step-by-step explanation:</u>

t represents time and y represents the height.

Since we want to know when the ball hits the ground, find t when y = 0

Ball 1 starts at a height of 109 --> h = 109

0 = -16t² + 109

16t² = 109

$t^2=\dfrac{109}{16}\\$

$t=\sqrt{\dfrac{109}{16}}$

$t=\dfrac{\sqrt{109}}{2}$

t = 5.22

4 0

3 years ago

Read 2 more answers

What's the circumference of a circle with a diameter of 30 cm

Bingel [31]

C=<span>πd
C=</span><span>π*30
C=30</span>π<span>≈94.25 cm</span>

7 0

2 years ago

Read 2 more answers

What is the equation of the line below?

Licemer1 [7]

Answer:

$y = -\frac{2}{3}x + 1$

Step-by-step explanation:

The equation of the line shown can be expressed in the slope-intercept formula as $y = mx + b$

Let's find m = slope, and b = y-intercept.

Using two points on the line, (0, 1) and (1½, 0),

$slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 1}{\frac{3}{2} - 0} = \frac{-1}{\frac{3}{2}} = - \frac{2}{3}$

y-intercept, b is where the line intercepts the y-axis = 1.

To create an equation for the line, substitute m = -⅔, b = 1 in $y = mx + b$ .

✅The equation would be:

$y = -\frac{2}{3}x + 1$

4 0

3 years ago