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2 years ago

3. What is the Ngebraic expression for the following word phrase: the product of 4 more than x

Mathematics

2 answers:

serious [3.7K]2 years ago

7 0

Answer:

6(x+4) hope this helps

Step-by-step explanation:

NeX [460]2 years ago

3 0

6(x+4)

Hope this helps :)

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there are 2,300 licensed dogs in clarkson. A random sample of 50 of the dogs in Clarkson shows that 8 have ID microchips implant

algol [13]

Set up a ratio comparing the sample portion to the whole portion.

x= # of all dogs likely to have chip

Sample: 8 out of 50
Whole: x out of 2,300

8/50= x/2300
cross multiply

(50*x)= (8*2300)
50x= 18400

divide both sides by 50
x= 368

ANSWER: 368 dogs in Clarkson are likely to have a microchip.

Hope this helps! :)

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2 years ago

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What is 90a + (78b - 56e) - 46 + 981c ?

bija089 [108]

What is the variables replacement

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3 years ago

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At a music store, the price of a set of speakers is $245, plus the sales tax of 6.5%. What is the total cost of the speakers, in

amm1812

Its 6.0 i think im sory is wrong

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3 years ago

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Turn 15/9 to a decimal

navik [9.2K]

Answer:

1.67 this is rounded but original is just endless 6

Step-by-step explanation:

1 6/9

1 2/3

1.66

Hopes this help please mark brainliest

7 0

1 year ago

Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5

givi [52]

<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

$A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]$ $X=\left[\begin{array}{c}x\\y\end{array}\right]$

and $B= \left[\begin{array}{c}11\\5\end{array}\right]$

∴AX=B

$adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]$

$A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6$

∴ $A^{-1} =\frac{adj A}{|A|}$

So, $A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}$

$A^{-1} ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}$

$X =A^{-1}\times B$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c} {6}\\ {11} \end{array}\right]}$

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

7 0

2 years ago