Find the measures of each numbered angles

Mathematics

2 answers:

ZanzabumX [31]3 years ago

4 0

Answer:

∠ 1 = 109° , ∠ 2 = 29° , ∠ 3 = 71°

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180° , then

∠ 1 + 35° + 36° = 180°

∠ 1 + 71° = 180° ( subtract 71° from both sides )

∠ 1 = 109°

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∠ RVU and ∠ 1 are adjacent angles on a straight line and sum to 180° , then

∠ RVU + ∠ 1 = 180°

∠ RVU + 109° = 180° ( subtract 109° from both sides )

∠ RVU = 71°

In Δ RVU

∠ 2 + 80° + 71° = 180° ( sum of angles in triangle )

∠ 2 + 151° = 180° ( subtract 151° from both sides )

∠ 2 = 29°

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∠ 3 and ∠ RVU are vertically opposite angles and are congruent , then

∠ 3 = 71°

Vsevolod [243]3 years ago

3 0

Δ UVT has: ∠V₁ = 180⁰ - ∠TUV - ∠VTU = 180⁰ - 35⁰ - 36⁰ = 109⁰

We have: ∠RVU = ∠V₃ = 180⁰ - ∠V₁ = 180⁰ - 109⁰ = 71⁰

ΔRVU has: ∠U₂ = 180⁰ - ∠URV - ∠ RVU = 180⁰ - 80⁰ - 71⁰ = 29⁰

Answer:

∠V₁ = 109⁰
∠U₂ = 29⁰
∠V₃ = 71⁰

Ok done. Thank to me :>

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A ball is shot straight up from the top of a 15-story building. The motion of the ball could be described by the function: h(t)=

viktelen [127]

Answer:

After 4 seconds the height is 480 meters.
The maximum height is 484 meters.
The ball hits the ground after 10 seconds

Step-by-step explanation:

The height after four seconds is h(4) = -16 * r² + 144*4+160 = 480

The maximum height of the ball is the value it takes at its vertex 'v = -b/2a'. In this case a = -16 and b = 144, so the v = -144/-32 = 4.5. The maximum height of the ball as a result is h(4.5) = -16 (4.5)² + 144*4.5 + 160 = 484

To find the moment the ball hits the ground, we need to find when h takes the value 0 by using the quadratic formula, with a = -16, b = 144 and c = 160.

$r_1,r_2 = \frac{-144 \, ^+_- \sqrt{144^2-4*(-16)*160}}{2*(-16)} = \frac{-144 \, ^+_- \sqrt{30976}}{-32} = \frac{-144 \, ^+_- 176}{-32} = -1, 10$