Pie equals 3.14 so if you turn that into a fraction you will get your answer
Let event A = Caroline buys fruit, event B = Caroline buys CD, Ac and Bc are complementary events.
Events AB, ABc, AcB and AcBc are jointly exhaustive and disjoint, hence P(AB) + P(ABc) + P(AcB) +P(AcBc) =1.
Events A and B independent, hence Ac and Bc independent too and probability P(AcBc) = P(Ac)*P(Bc) = (1 - P(A))(1-P(B)) = 0.6*0.4 = 0.24.
Required probability P(AB + ABc + AcB ) = P(AB) + P(ABc) + P(AcB) = 1- P(AcBc) = 1 - 0.24 = 0.76.
Answer: Probability that Caroline buys fruit, a CD or both is 0.76.
It isn't different, it is very much the same
1-1 = 0
.1-.1 = 0
5.25 - 3.75 = 1.50
1.0005 +1.005 = 2.0055
just make sure to line the decimal places on top of each other <span />
Exact Form: w = − 8 9 Decimal Form: w = − 0. ¯ 8
Answer:
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Step-by-step explanation:
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