First, solve for the volume of the ball bearings by the equation,
V = πd³ / 6
Substituting the value of diameter given,
V = π(1 cm)³ / 6 = π/6 cm³ = 0.5236 cm³
Divide the amount of material given by this volume,
n = 5.24 cm³ / <span>0.5236 cm³ = 10
Therefore, there are 10 ball bearings that may be formed.</span>
X^5 - x^4 - 2x^3 + 10x - 1/9 is the standard form
Obtuse, acute, and right.
Answer:
Step-by-step explanation:
sin(x)=1.5/2.6
x=35.2
