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Mnenie [13.5K]
3 years ago
9

(-----×1/4)÷6×3/9 I need the step to this problem so that I explain to my grandson how he he gets the answer

Mathematics
1 answer:
lesya692 [45]3 years ago
6 0

Answer:

-----×1/72

Step-by-step explanation:

The <em>order of operations</em> says do these operations in order left to right. Please note that ÷ means the same as / unless you define it otherwise in your problem statement.

If you intend the ÷ symbol to be used to indicate everything to its left is divided by everything to its right, it is appropriate to use parentheses for that grouping, as in ...

  (-----×1/4)÷(6×3/9) = (-----×1/4)÷2 = -----×1/8

_____

Here, we're going to evaluate what you have written according to the usual rules as described above.

  (-----×1/4)÷6×3/9 = -----×1/24×3/9 = -----×(3/24)/9

  = -----×1/8/9

  = -----×1/72

_____

<em>Comment on the arithmetic</em>

Fractions are multiplied and divided in the usual way:

  a/b×c = (a×c)/b

  a/b/c = (a/b) × (1/c) = a/(b×c)

___

<em>Comment on fractions and parentheses</em>

Please note that parentheses are required on any numerator or denominator that consists of anything other than a single number or variable. (The exception is the case where the numerator is a product, because a·b/c = (a·b)/c with or without the parentheses.)

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a daily newspaper has 10225 subscribers when it began publication. six years old later it has 8200 subscribers what is the avera
seraphim [82]

Answer:

The rate of change in number of subscriber for the six years is 3.62%

Step-by-step explanation:

Given as :

The initial subscriber of newspaper = p = 10225

The subscriber of newspaper after 6 years of publish = P = 8200

The time period = t = 6 years

Let The average yearly rate of change = r%

<u>Now, According to question</u>

The subscriber of newspaper after n years = initial subscriber × (1-\dfrac{\textrm rate}{100})^{\textrm time}

Or, P = p × (1-\dfrac{\textrm r}{100})^{\textrm t}

Or, 8200 = 10225 × (1-\dfrac{\textrm r}{100})^{\textrm 6}

Or, \dfrac{8200}{10225} =  (1-\dfrac{\textrm r}{100})^{\textrm 6}

Or, 0.80195 =  (1-\dfrac{\textrm r}{100})^{\textrm 6}

<u>Taking power \dfrac{1}{6} both side</u>

So, (0.80195 )^{\frac{1}{6}} = ((1 - \frac{r}{100} )^{6})^{\frac{1}{6}}

Or, 0.9638 = 1 - \dfrac{r}{100}

Or,  \dfrac{r}{100} = 1 - 0.9638

Or,  \dfrac{r}{100} = 0.0362

Or, r = 0.0362 × 100

i.e r = 3.62

So, The rate of change in subscriber = 3.62%

Hence, The rate of change in number of subscriber for the six years is 3.62% . Answer

4 0
3 years ago
Find the total in the account with the following facts monthly contributions =$180 employer matching 25% interest rate 4.99% yea
algol13

Answer:

The amount that will be in the account after 38 years is $ 36811,05

Step-by-step explanation:

a)

For resolved this exercise used the next equation

R(1-(1 + i)--) Ap = ... (1)

Ap = Amount in account

R = Paid monthly

i = Monthly interest rate

t = Months for paid

Dates

i=- 2.05% 12 = 0,1708% = 0.0017

The interest is divided for 12 because is annual and the formula is mensual

t = 15yearsx12 = 180 months

             R = 220$

R(1-(1 + i)-) Ap =

220(1-(1 + 0.0017)-180) Ap = 0.0017

162,04 Ap=0.0017

Ap = 95321,855

The amount that will be in the account after 15 years is $ 95,321.85

b)

R(1-(1 + i)--) Ap = ... (1)

Ap = Amount in account

R = Paid monthly

i = Monthly interest rate

t = Months for paid

i=- 4,99% -= 0,415% = 0.0041

The interest is divided for 12 because is annual and the formula is mensual

t = 38yearsx12 = 456 months

             R = 180$

R(1-(1 + i)-) Ap =

Ap = 180(1-(1 + 0.0041) -456 0.0041

Ap = 36811,055

The amount that will be in the account after 38 years is $ 36811,05

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