(-----×1/4)÷6×3/9 I need the step to this problem so that I explain to my grandson how he he gets the answer

Mathematics

1 answer:

lesya692 [45]3 years ago

6 0

Answer:

-----×1/72

Step-by-step explanation:

The order of operations says do these operations in order left to right. Please note that ÷ means the same as / unless you define it otherwise in your problem statement.

If you intend the ÷ symbol to be used to indicate everything to its left is divided by everything to its right, it is appropriate to use parentheses for that grouping, as in ...

(-----×1/4)÷(6×3/9) = (-----×1/4)÷2 = -----×1/8

_____

Here, we're going to evaluate what you have written according to the usual rules as described above.

(-----×1/4)÷6×3/9 = -----×1/24×3/9 = -----×(3/24)/9

= -----×1/8/9

= -----×1/72

_____

Comment on the arithmetic

Fractions are multiplied and divided in the usual way:

a/b×c = (a×c)/b

a/b/c = (a/b) × (1/c) = a/(b×c)

___

Comment on fractions and parentheses

Please note that parentheses are required on any numerator or denominator that consists of anything other than a single number or variable. (The exception is the case where the numerator is a product, because a·b/c = (a·b)/c with or without the parentheses.)

You might be interested in

Which points are the verticles of the ellipse? Equations of ellipse

Mashutka [201]

Answer:

This question is solved in detail below. Please refer to the attachment for better understanding of an Ellipse.

Step-by-step explanation:

In this question, there is a spelling mistake. This is vertices not verticles.

So, I have attached a diagram of an ellipse in which it is clearly mentioned where are the vertices of an ellipse.

Vertices of an Ellipse: There are two axes in any ellipse, one is called major axis and other is called minor axis. Where, minor is the shorter axis and major axis is the longer one. The places or points where major axis and minor axis ends are called the vertices of an ellipse. Please refer to the attachment for further clarification.

Equations of an ellipse in its standard form:

$\frac{x^{2} }{a^{2} } + \frac{y^{2} }{b^{2} } = 1$