Answer:
Solution ( 
, 
)
Step-by-step explanation:
Given : 3x - 2y = 12 and 6x + 3y = 21.
To find : Solve the system of equations and choose the correct ordered pair.
Solution : We have given
3x - 2y = 12 -------(1)
6x + 3y = 21-------(2)
Multiplying the equation(1) by 2 , it become.
6x - 4y = 24 .
Now subtract it from equation (2).
6x + 3y = 21
(-)6x - (+)4y = (-)24 .
____________
0 + 7y = -3.
On dividing both sides by 7.
y = .
Plug the y = in equation 2 .
6x + 
= 21
6x + 
= 21.
On multiplying both sides by 7
42x -9 = 21 *7 .
42x -9 = 147 .
On adding both sides by 9
42x = 147 + 9 .
42x = 156.
On dividing both sides by 42.
x = 
.
x = .
Therefore, Solution ( , )
Eatin time is 8 pm....her meal takes 65 minutes to cook...well, 60 minutes is an hr...so that knocks it down to 7 pm....and then we take away the 5 minutes....so we put the food in the oven at 6:55 pm....oh...on a 24 hr clock...that's 18:55
Answer:
D
Step-by-step explanation:
You are subtracting two functions to get the profit, the formula is p(x)=r(x)-c(x). You know what two of those functions are equivalent to so plug it in to get
p(x)=11x-(6x+20)
to solve you must first get rid of the parentheses by distributing the negative.
p(x)=11x-6x-20
then, combine like terms (both x's)
p(x)=5x-20
That is your final answer.
Multiplication gives
us distribution over the products, so
(a′+b+d′) (a′+b+c′+f′)
= a′ (a′+b+c′+f′) + b (a′+b+c′+f′) + d′ (a′+b+c′+f′)
And then you can
then distribute again each of the factors on the right.
Then you should simplify
in any given number of ways. To take as an example, you have a′b and ba′,
and since a′b + a′b = a′b + a′b = a′b, you can just drop one of them.
Since bb = b, you can rewrite bb as b and etc.
So in the end
part we should arrive at a sum of products. Then you can just invert. For
example, if at the end you had:
p′ = a′b + bc′ +
d′f ′+ a′f′
Then we would
have
p = p′′ = (a′b +
bc′ + d′f′ + a′f′)′ = (a′b)′⋅(bc′)′⋅(d′f′)′⋅(a′f′)′
Then applying De
Morgan's laws to each of the factors, e.g., (a′b)′ = a+b′, so we would
have
p = (a+b′)⋅(b′+c)⋅(d+f)⋅(a+f)
which is a
product of sums.
