Gvvv. Dbbznxbdncbndbzbsbxbdbdjdbdbdbdbdjdbdjd
Answer:
D: -4 to 4, R: -3 to 6
Step-by-step explanation:
m∠BAC = 27°
Solution:
ABCD is a quadrilateral.
AB and CD are parallel lines.
Given m∠BCD = 54°
AC bisect ∠BCD.
m∠DCA + m∠CAB = m∠BCD
m∠DCA + m∠DCA = 54° (since ∠ACB = ∠DCA)
2 m∠DCA = 54°
Divide by 2 on both sides, we get
m∠DCA = 27°
AB and CD are parallel lines and AC is the transversal.
<em>If two parallel lines cut by a transversal, then the alternate interior angles are equal.</em>
m∠BAC = m∠DCA
m∠BAC = 27°
Hence m∠BAC = 27°.
1. A property a parallelogram must have is that adjacent angles must be supplementary, they add up to 180º. We are given the values of the adjacent angles U and T. Their sum must add up to 180º. Solve for x.
<span>U + T = 180 </span>
<span>5x + 2x - 9 = 180 </span>
<span>7x - 9 = 180 </span>
<span>7x = 189 </span>
<span>x = 27 </span>
<span>Substitute this value of x for itself in angle T. </span>
<span>T = 2(27) - 9 </span>
<span>T = 54 - 9 </span>
<span>T = 45, (D) is the answer </span>
