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vaieri [72.5K]
2 years ago
13

Julia takes out a loan to buy a new car. She borrows £8000 over 5 years at a simple interest rate of 10%.

Mathematics
2 answers:
Elodia [21]2 years ago
4 0

Answer:

Julia will pay £4000 as interest.

Step-by-step explanation:

As per given question we have provided that :

  • ➣ Principal = £8000
  • ➣ Time = 5 years
  • ➣ Rate = 10%

Here's the required formula to find the Principal :

{\longrightarrow{\pmb{\tt{I= \dfrac{PRT}{100}}}}}

  • ↝ I = Interest
  • ↝ P = Principal
  • ↝ R = Rate
  • ↝ T = Time

Substituting all the given values in the formula to find the Principal :

{\implies{\sf{Interest= \dfrac{PRT}{100}}}}

{\implies{\sf{Interest= \dfrac{P \times R \times T}{100}}}}

{\implies{\sf{Interest= \dfrac{8000 \times 10 \times 5}{100}}}}

{\implies{\sf{Interest= \dfrac{80 \cancel{00} \times 10 \times 5}{1 \cancel{00}}}}}

{\implies{\sf{Interest= 80 \times 10 \times 5}}}

{\implies{\sf{Interest= 800 \times 5}}}

{\implies{\sf{\underline{\underline{Interest = 4000}}}}}

Hence, the interest is £4000.

\rule{300}{2.5}

Bumek [7]2 years ago
3 0

Answer:

here,

principle(p)=£8000

time(t)=5 years

rate(r)=10%

now,

Interest=PTR/100

         =8000 x 5 x 10/100

        =£4000

Step-by-step explanation:

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The data sets show the years of the coins in two collections. Derek's collection: 1950, 1952, 1908, 1902, 1955, 1954, 1901, 1910
KATRIN_1 [288]

Answer:

Derek's collection :

Mean= 1929

Median= 1930

Range= 54

IQR = 48

MAD= 23.75

Paul's collection:

Mean= 1929

Median= 1929.5

Range= 15

IQR = 6

MAD= 3.5

Step-by-step explanation:

1950, 1952, 1908, 1902, 1955, 1954, 1901, 1910

Mean is given by:

(1950+1952+ 1908+1902+1955+1954+1901+1910)/8

=1929

absolute deviation from mean is:

|1950-1929|= 21

|1952-1929|= 23

|1908-1929|= 21

|1902-1929|= 27

|1955-1929|= 26

|1954-1929|= 25

|1901-1929|= 28

|1910-1929|= 19

from the mean of absolute deviation gives the MAD of the data i.e.

(21+23+21+27+26+25+28+`9)/8

23.75

 

:arrange the given data to get the range and median

   1901   1902    1908   1910    1950  1952    1954   1955

The minimum value is: 1901

Maximum value is: 1955

Range is: Maximum value-minimum value

         Range=1955-1901

Range= 54

median is (1910+1950)/2

1930

   the lower set of data=

  1901   1902    1908   1910

first quartile becomes

1902+1908)/2

Q1=1905

and upper set of data is:

1950  1952    1954   1955

we find the median of the  upper quartile or third quartile is:

1952+1954)/2=1953

Q3-Q1=1953-1905=

IQR=48

 

Paul's collection:

1929, 1935, 1928, 1930, 1925, 1932, 1933, 1920

Mean is given by:

1929+1935+ 1928+ 1930+ 1925+ 1932+1933+1920)/8

1929

absolute deviation from mean is:

|1929-1929|=0

|1935-1929|= 6

|1928-1929|= 1

|1930-1929|= 1

|1925-1929|= 4

|1932-1929|= 3

|1933-1929|= 4

|1920-1929|= 9

Hence, we get:

MAD=0+6+1+1+4+3+4+9/8

28/8

3.5

arrange the data in ascending order we get:

1920   1925   1928   1929   1930   1932   1933   1935  

Minimum value= 1920

Maximum value= 1935

Range=  15 (  1935-1920=15 )

The median is between 1929 and 1930

Hence, Median= 1929.5

Also, lower set of data is:

1920   1925   1928   1929  

the first quartile or upper quartile is

1925+1928/2

1926.5

and the upper set of data is:

1930   1932   1933   1935  

We have

1932+1933)/2

1932.5

IQR is calculated as:

Q3-Q1

6

7 0
3 years ago
The ratio of the side lengths of a quadrilateral is2:3:5:6, and its perimeter is 48 cm. what is the length of the longest side
inessss [21]
6 times 8 is 48 and don't be lake


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I have homework and i dont understand it its called "Solving Systems of Equations by Elimination." The problem im stuck on is
Goshia [24]
8x + y = -16 ;
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If 596 people voted in the election, how many were over 65 years old?
damaskus [11]

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2 years ago
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the population of collin county, which follows the exponential growth model, increased from 491,675 in 2000 to 782,341 in 2010.
CaHeK987 [17]

Applying the formula for the exponential growth model, the growth rate is  0.046447277776453351798354258063923

the exponential growth is a data pattern that illustrates an increase over time by generating an exponential function curve.

The exponential growth model can be expressed as:

P(t) = P(0) x e^(k.t)

Where:

P(t) = Value at time t

P(0) = Initial value

k = growth rate

Information from the problem:

P(0) = 491,675

P(t) = 782,341

t = 2010 - 2000 = 10 years

Substitute the data into the formula:

782,341 = 491,675 x e^{10k}

e^{10k} = 782,341 / 491,675

10 k . ln e = ln (782,341 / 491,675)

10 k = 0.46447277776453351798354258063923

k = 0.046447277776453351798354258063923

Read more about the exponential growth model here:

brainly.com/question/14973088

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8 0
1 year ago
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