Well mars have a low mass compared to the earth <span>the mass of mars is 38% </span>
Check the picture below.
notice that the point A is the center of the circle, and thus the ∡BAF is a central angle, and the arc BF gets its angle measurement from ∡BAF, in red.
now, notice, ∡BAF has a twin
vertical angle, namely ∡CAE in green, and the arc made by ∡CAE is congruent to BF.
Around $634.85 per year
Because:
$32.85+$35(12 months)+$3.5(52 weeks in a year)= Total cost per year
$420 $182
$32.85 + $420 + $182 = $634.85 per year
Parameterize the line segments (call them
and
, respectively, by


both with
. Then



The rule to use: when dividing fractions, invert and multiply.
-6 ÷ -(3/4) equals -6 * -(4/3) which equals 24 / 3 which equals
8