The volume of the frustum is volume of the whole cone(A) minus the smaller cone(B) which is would give the volume of frustum(C) = 256cm³
<h3>Calculation of a frustum</h3>
The volume of cone A V=πr²h/3
Where radius = 20cm
The volume of cone B = V=πr²h/3
Where radius = 12cm
Therefore volume of frustum =
V=π * 20² * h/3 - π * 12² *h/3
The variables will cancel out each other
V = 20² - 12²
V = 400- 144
V = 256cm³
Therefore, the volume of the frustum(C) = 256cm³
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1.x^2 +6x - 4 = 6x
X^2 + 6x -4 - 6x = 0
X^2 - 4 = 0
By difference of two squares :
X^2 - 4 = 0 can be written as (x-2) (x+2) = 0
(X-2)=0 therefore x= 2
(X+2)=0 therefore x= -2
2. X^2 - 8x = -6x
X^2 -8x + 6x = 0
X^2 - 2x = 0
X(X-2) = 0
X= 0, X= 2
A = (1/2)bh [b = 10 m, h = 6 m]
A = (1/2) * 10 * 6 = 30 m²
Answer:
Each girl gets 2 1/2.
Step-by-step explanation:
5 is an odd number. If you take the 4 in it and split that in half then you have 2. Then take the extra 1 from the rest of 5 and split that in half.
2 1/2.
Answer:
90
Step-by-step explanation:
Multiple the number of all your options.
6 x 3 x 5 = 90
