Answer:
Step-by-step explanation:
the anwser is 1/3
30b³ + 20b² + 15b + 10 = ...(:5)
6b³ + 4b² + 3b + 2 =
6b³ + 3b + 4b² + 2 =
3b(2b²+1) + 2(2b²+1) =
(2b²+1)*(3b+2)
Let x be the first number
Let y be the second number
x+y=61
x-y=37 --> x=37+y
(37+y)+y=61
37+2y=61
2y=61-37
2y=24
y=12
x+y=61
x+12=61
x=61-12
x=49
Therefore the numbers are 49 and 12
Hope I helped :)
Answer:
y = -3x + 3
Step-by-step explanation:
use the formula y - y1 = m ( x - x1)
y - 3 = -3 ( x - 0)
y - 3= -3x
y = -3x + 3