How do I figure this out

What is the solution to the equation

Elis [28]

Answer:

x = -13

Step-by-step explanation:

Distribute:

8 - 6x + 10x - 15 = 20 - 5x

Combine like terms:

4x - 7 = 20 - 5x

Isolate Variable

-x = 13

-1(-x) = -1(13)

x = -13

8 0

2 years ago

Read 2 more answers

Which of the following are valid names for the given triangle? Check all that apply.

vfiekz [6]

When naming triangles we name them by the letters on each corner so only answers with T, A, and X in them are correct, so TAX, XTA, and AXT

6 0

2 years ago

Read 2 more answers

Solve for x. Round your answer to the nearest tenth.

zlopas [31]

Answer:

By Pythagorean theorem:

$c^2=a^2+b^2$

$x=\sqrt{15^2+33^2}$

$x=36.25$

$x=36.3$

7 0

2 years ago

A group of individuals were surveyed about their plans for vacation. There were 21 individuals who said they were going to the d

Alexeev081 [22]

Answer:

140 individuals were surveyed

42 people are planning on going to the mountains

Step-by-step explanation:

The question is missing the information regarding the percentage of people who said that they were going to each of the possible destinations. After a quick google search I've found that, in the original question, 32% of individuals were going to the beach, 15% to the desert, 23% to major cities, and 30% to the mountains.

If 21 people said they were going to the desert, and that corresponds to 15% of the total number of people surveyed, the number of people surveyed is:

$21=n*0.15\\n=140\ individuals$

140 individuals were surveyed

Since 30% responded "the mountains", the number of people planning on going to the mountains is:

$m = 140*0.30\\m=42\ people$

42 people are planning on going to the mountains

3 0

2 years ago

In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the

earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

A = video components need repair within 1 year

B = electronic components need repair within 1 year

C = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events A, B and C are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

$=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278$

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

$=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277$

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

7 0

2 years ago