<h3>
1.Area of the parallelogram= 288 square units</h3><h3>
2.Area of the parallelogram=45 </h3><h3>
3.Area of the trapezoid = 34 square in.</h3><h3>
4.Area of the trapezoid = 8 square ft</h3><h3>
5.Area of the rhombus= 27 square cm</h3><h3>
6.Area of the rhombus= 108 square in</h3><h3>
7.The area of the desktop is = 1200 square in</h3><h3>
8.The area of the rhombus is =84 </h3><h3>
9.Area of the trapezoid = 240 square ft</h3>
Step-by-step explanation:
1.
Base =16 ft and Height = 18 ft
Area of the parallelogram = base × height
=16× 18 square units
= 288 square units
2.
Base = 9 m and height = 5 m
Area of the parallelogram = base × height
=(9×5)
=45
3 .
Height = 4 in and parallel sides are 12 in and 5 in
Area of the trapezoid =
square in.
= 34 square in.
4.
Height = 2 ft and parallel sides are 2 ft and 6 ft
Area of the trapezoid =
square ft
= 8 square ft
5.
Diagonals are 6 cm and 9 cm.
Area of the rhombus
square cm
= 27 square cm
6. Diagonals are 12 in and 18 in
Area of the rhombus
square in
= 108 square in
7. Given a desktop in the shape of a parallelogram has a base 30 in. and a height of 40 in
The area of the desktop is = (30 × 40 ) square in
= 1200 square in
8. Given , a rhombus has one diagonal that is 14 cm and other diagonal 12 cm.
The area of the rhombus =
=84
9.Given , the base of trapezoid are 24 ft and 16 ft and height is 12 ft
Area of the trapezoid =
= square ft
= 240 square ft
we are given
highest exponent is 3
degree is the highest exponent
so, degree is 3
You want to multiply 87.60 and 25.60 by 10. 87.60x10=876. 25.60x10=256.876-256=620. Then you will take 1/4 of 620 to get the answer 155 is what she paid for lessons.
Answer:
4/3
Step-by-step explanation:
encontrar el mínimo común denominadorienes para que sea mas facil
5/3+17/51-14/21 es 5/3 + 1/3 -2/3 cuando todos son igual de los denominados.
Ahora escribi todos los 3 numeros que iguale lo mismo denominador
5+1-2/3
Ahora solo hace el mas y menos y esta listo
4/3 es lo que pasa cuando haces las operaciones.
-4 next to x value means the graph is moved 4 units to the right
+5 on the end of the function means the graph is moved up 5 units