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laila [671]
3 years ago
10

IQ test scores are normally distributed with a mean of 100 and a standard deviation of 15. An individual's IQ score is found to

be 120. Find the z-score corresponding to this value.
Mathematics
1 answer:
kipiarov [429]3 years ago
5 0

Answer:

Step-by-step explanation:

(score - mean)/stand dev = z score

(120 - 100) / 15 = 1.33 z score = .9082

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Given right angle ABC, what the value of tan(A)?
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Hi there!

\large\boxed{12/5}}

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6 0
3 years ago
NEED HELP ASAP!!
galina1969 [7]

The distance of the ship from the lighthouse can be determined using

trigonometric ratios.

  • The ship's horizontal distance from the lighthouse is approximately  <u>1,303.03 feet</u>.

Reasons:

The given parameters are;

The height of the beacon-light above the ground = 114 feet

The angle of elevation to the beacon measured by the boat crew = 5°

Required:

The horizontal distance of the ship from the lighthouse

Solution:

The beacon-light that is seen by the boat crew, the height of the beacon light, and the horizontal distance of the ship from the lighthouse form a right triangle.

Therefore, we have;

\displaystyle tan (\theta) = \mathbf{ \frac{Opposite}{Adjacent}}

\displaystyle tan(angle \ of \ elevation) = \mathbf{\frac{Height \ of \ beacon \ light}{The \ ship's \ horizontal \ distance \ from \ the \ lighthouse}}

Which gives;

\displaystyle The \ ship's \ horizontal \ distance \ from \ the \ lighthouse=  \frac{Height \ of \ beacon \ light}{tan(angle \ of \ elevation)}

Therefore;

\displaystyle The \ ship's \ horizontal \ distance \ from \ the \ lighthouse=  \frac{114 \ feet}{tan(5^{\circ})} \approx \mathbf{1,303.03 \ feet}

The ship's horizontal distance from the lighthouse = <u>1,303.03 feet</u>.

Learn more about angle of elevation here:

brainly.com/question/15821537

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