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3 years ago

Which polynomial is equivalent to (3z + 1)(z + 1)?

Mathematics

2 answers:

Keith_Richards [23]3 years ago

8 0

3z^2 + 4z + 2
Believe this is correct

Olin [163]3 years ago

7 0

Answer:

3z^2 + 4z+1

Step-by-step explanation:

(3z + 1)(z + 1)

we multiply it to get the polynomial

Apply FOIL method to multiply

Multiply 3z with z+1 first

3z *z = 3z^2

3z * 1 = 3z

Now multiply 1 with z+1

1*z= 1z

1*1= 1

Now we write all the terms together

3z^2 + 3z +1z +1

Combine like terms

3z^2 + 4z+1

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Simplify.<br> (WILL GIVE BRAINLIEST)

Novosadov [1.4K]

Answer:

$\frac{\sqrt{x} }{2x}$

Step-by-step explanation:

Rationalize the denominator first (keep in mind we are NOT solving this because there is no equals sign here. We are merely simplifying.)

$\frac{\sqrt{5x} }{x\sqrt{20} } *\frac{\sqrt{20} }{\sqrt{20} } =\frac{\sqrt{100x} }{20x}$

Now simplify by taking the square root of 100 to get:

$\frac{10\sqrt{x} }{20x}$

Divide numerator and denomiator by 10 to get:

$\frac{\sqrt{x} }{2x}$

4 0

3 years ago

Please help me with average

Anvisha [2.4K]

Answer:

2x+1

Step-by-step explanation:

(3x-5)+(x+2)+(2x+6)=6x+3

6x+3/3=2x+1

8 0

3 years ago

Read 2 more answers

Plz with steps .. it's very hard can anyone plz

liubo4ka [24]

Answer:

Step-by-step explanation:

$\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a} \qquad f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a} \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} }{\dfrac{1}{2\sqrt{x}} }\\\\$

$\displaystyle \lim_{n \to a} \dfrac{2\sqrt{x} }{\sqrt{2x}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}} =\lim_{n \to a} \dfrac{2 }{\sqrt{2}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3*\sqrt{a} }{\sqrt{2a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3}{\sqrt{2}}\\\\\\=-\ \dfrac{1}{\sqrt{2}}\\\\$

7 0

2 years ago

Meredith was paid $18 for recycling 30 pounds glass. What is this rate payment

hammer [34]

$1.67 for each pound of glass

3 0

3 years ago

the first box measures 18 inches by 8 inches by 15 inches. the second box is 10 inches tall and the area of the base measures 19

Mandarinka [93]

Answer:

Box 1 has the greater volume, by 200 in³

Step-by-step explanation:

The largest of two volumes can be found by computing each volume and comparing the results.

The volume is computed from dimensions by ...

V = LWH

V = (18 in)(8 in)(15 in) = 2160 in³

The volume is computed from area and height by ...

V = Bh . . . . . where B is the base area, and h is the height

V = (196 in²)(10 in) = 1960 in³

<h3>Comparison</h3>

The units of the two volumes are the same, so we can decide which is larger by comparing the numbers. Box 1 has a volume that is more than 2000 in³, and Box 2 has a volume that is less than 2000 in³.

Box 1 has a greater volume

The amount by which the volume is greater can be found by subtracting the smaller volume from the larger:

2160 in³ -1960 in³ = 200 in³

Box 1 is larger by 200 in³

_____

<em>Additional comment</em>

The percentage by which Box 1 is larger than Box 2 can be found by multiplying 100% by the ratio of the difference to the Box 1 volume:

200/1960 × 100% ≈ 10.2%

Box 1 is about 10% larger than Box 2.

3 0

2 years ago

Read 2 more answers