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vazorg [7]
2 years ago
10

What is the sum? StartFraction 3 Over x squared minus 9 EndFraction StartFraction 5 Over x 3 EndFraction.

Mathematics
1 answer:
V125BC [204]2 years ago
6 0

The sum of the two fractional number, which consist in the variable <em>x</em> is in the polynomial function,

f(x)=\dfrac{5x-12}{(x+3)(x-3)}

<h3>What is the sum of fraction number?</h3>

Fraction number is the number which is a part of a whole number. It is written with a numerator and denominator.

Fraction number are written as,

\dfrac{a}{b}

Here (a) is the numerator and (b) is the denominator.

To find the sum of two fraction numbers, cross multiply both the numbers or find the least common factor as denominator.

The first fraction number given in the problem is,

\dfrac{3}{x^2+9}

The second fraction number given in the problem is,

\dfrac{5}{x+3}

Let the sum of these number is f(x). Thus,

f(x)=\dfrac{3}{x^2-9}+\dfrac{5}{x+3}\\f(x)=\dfrac{3}{(x+3)(x-3)}+\dfrac{5}{x+3}\\

Solve it further as,

f(x)=\dfrac{3+5(x-3)}{(x+3)(x-3)}\\f(x)=\dfrac{3+5x-15}{(x+3)(x-3)}\\f(x)=\dfrac{5x-12}{(x+3)(x-3)}

Thus, the sum of the two fractional number is,

f(x)=\dfrac{5x-12}{(x+3)(x-3)}

Learn more about the fraction number here:

brainly.com/question/78672

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Select ALL the sets of three side lengths that will make a triangle.
konstantin123 [22]

Answer:

7 + 6

5 + 11

Step-by-step explanation:

the lengths of the two shorter sides of a triangle must add up to more than the length of the third side.

3 + 4 = 7 ≤ 8    no

7 + 6 = 13 > 12   yes

5 + 11 = 16 > 13  yes

4 + 6 = 10 ≤ 12  no

4 + 6 = 10 ≤ 10  no

6 0
3 years ago
Read 2 more answers
8) Factor each sum or difference of cubes completely.<br> a. 8x3 + 27
ASHA 777 [7]

Answer:

\large\boxed{(2x+3)(4x^2-6x+9)}

Step-by-step explanation:

8=2^3\\\\8x^3=2^3x^3=(2x)^3\\\\27=3^3\\\\8x^3+27=(2x)^3+3^3\qquad\text{use}\ a^3+b^3=(a+b)(a^2-ab+b^2)\\\\=(2x+3)\bigg((2x)^2-(2x)(3)+3^2\bigg)=(2x+3)(4x^2-6x+9)

4 0
3 years ago
Pls solve the simultaneous equation in the attachment.
siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

\frac{x}{2}-\frac{y}{5}=1 ----> equation A

y-\frac{x}{3}=8 ----> equation B

Multiply equation A by 10 both sides to remove the fractions

5x-2y=10 ----> equation C

isolate the variable y in equation B

y=\frac{x}{3}+8 ----> equation D

we have the system of equations

5x-2y=10 ----> equation C

y=\frac{x}{3}+8 ----> equation D

Solve the system by substitution

substitute equation D in equation C

5x-2(\frac{x}{3}+8)=10

solve for x

5x-\frac{2x}{3}-16=10

Multiply by 3 both sides

15x-2x-48=30

15x-2x=48+30

Combine like terms

13x=78

x=6

<em>Find the value of y</em>

y=\frac{x}{3}+8

y=\frac{6}{3}+8

y=10

The solution is the ordered pair (6,10)

Part b) we have

xy=21 ---> equation A

x+5y=22 ----> equation B

isolate the variable x in the equation B

x=22-5y ----> equation C

substitute equation C in equation A

(22-5y)y=21

solve for y

22y-5y^2=21

5y^2-22y+21=0

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

x=22-5(1.4)=15

For y=3

x=22-5(3)=7

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0
4 years ago
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