substitute x for y-1
2(y-1)-y=6 distribute
2y-2-y=6 subtract y in 2y
y-2=6 add 2 to get y by itself
y=8
Put y back into equation x=y-1
x=8-1
X=7
If you actually draw the coordinates, it should be a parallelogram.
Answer:
59
Step-by-step explanation:
5au+24av-5bu-30bv
rearrange it
5au+5bu-24av-30bv
similar letter cross each other
5a+5b-24a-30b
rearrange it
5a+24a-5b-30b
similar letter cross each other
5+24-5-30
29- -30=59
-and - = +
Assuming linear.
if k is at (3,4) and j is at (-8,7)
set. (y1,x1) and(y2,x2)
[(y2-y1),(x2-x1)]
[(-8-3),(7-4)]
distance from k to j is (-11,3)
now take coordinates of j and distance from. k->j and add them to get coordinate for L
[(-11+(-8)),(7+3)]= (-19,10)=L
Parallel should be your answer!