Given:
Point S is translated 5 units to the left and 12 units up to create point S'.
To find:
The distance between the points S and S'.
Solution:
Point S is translated 5 units to the left and 12 units up to create point S'.
The diagram for the given problem is shown below.
From the below figure it is clear that the distance between the point S and S' is the height of a right triangle whose legs are 5 units and 12 units.
By Pythagoras theorem,
Taking square root on both sides.
Therefore, the distance between S and S' is 13 units.
Well, since we know is a geometric sequence, we can always get the common ratio of it by simply dividing one value by the one behind it... so let's do so, with say hmm -32 and 8 -32/8 = -4 <-- our common ratio
the first term is -2
Answer:
+ 9x +18
Step-by-step explanation:
multiply the parentheses together (x × x)=x² and x×6=6x then do 3×x which will equal 3x and then multiply 3 and 6 which is 18
now combine like terms (x²+6x+3x+18)
6+3=9 so now you will have x²+9x+18
Answer:
B. a = 5
Step-by-step explanation:
3(a - 4) + 1 = 9 - a
Distribute the 3 into the parenthesis.
3a - 12 + 1 = 9 - a
Add -12 and 1.
3a - 11 = 9 - a
Add a to both sides.
4a - 11 = 9
Add 11 to both sides.
4a = 20
Divide both sides by 4.
a = 5.
Proof:
3(a - 4) + 1 = 9 - a
Substitute variable.
3(5 - 4) + 1 = 9 - 5
Subtract inside parenthesis.
3(1) + 1 = 9 - 5
Multiply 3 and 1.
3 + 1 = 9 - 5
Add 3 and 1.
4 = 9 - 5
Subtract 5 from 9.
4 = 4.
Answer:
51.23
Step-by-step explanation:
