It hits the ground at h=0
0=-16t^2-16t+96
undistribute -16
0=-16(t^2+t-6)
factor
0=-16(t-2)(t+3)
set to zero
0=t-2
2=t
t+3=0
t=-3, nope, we can't have negative time
at t=2, or 2 seconds
The area shaded in green is 864 cm²
<h3>Similar figures</h3>
Similar figures, corresponding angles are congruent and the sides are ratio of each other. Therefore,
AB / PQ = CD / RS
30 / 10 = 24 / RS
30RS = 240
RS = 240 / 30
RS = 8 cm
let find the height of trapezium PQRS.
AB / PQ = 36 / h
30 / 10 = 36 / h
30h = 360
h = 360 / 30
h = 12 cm
Therefore,
area of the green portion = area of ABCD - area of PQRS
<h3>Area of a trapezium</h3>
Therefore,
area of ABCD = 1 / 2(24 + 30)36 = 1 / 2 (54)36 = 1944 / 2 = 972 cm²
area of PQRS = 1 / 2(10 + 8)12 = 1 / 2(18)12 = 216 / 2 = 108 cm²
Area of the green portion = 972 - 108 = 864 cm²
learn more on trapezium here: brainly.com/question/11961445
2.2x and 4.4 have a GCF of 2.2. So, you can factor that out like so:
2.2x+4.4 = 2.2*x+2.2*2 = 2.2(x+2)
Hope this helps!
Yes..I think it is because the range is 5 and the domain is -1 (But im most likely wrong)
Ok since the athlete an equal distance of 2 days a week and he runs a total of 11 miles in 5 days you will need to think back so before he had 11 miles done next weak he had a total of 19 miles so you will start at 11 then count up to 19.
Use a number line to show how many days it took for the athlete to get 19 miles.
Then once you do the number line count the lumps and that’s how many days it took for the athlete to get 19 miles.
Hope this helped.
