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2 years ago

Use complete sentences to describe the transformation that maps ABCD onto its image.

Mathematics

1 answer:

Nadusha1986 [10]2 years ago

8 0

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

The required transformation that maps ABCD to its image is ~

" five units right and two units up "

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22 POINTS

MrRissso [65]

Answer:

5 feet

Step-by-step explanation:

In the height equation (notice the ball's horizontal distance traveled is not addressed here), each term means something.

'5' is where the ball started from, since that makes a difference where it winds up t seconds later. If you have trouble visualizing that, imagine if the ball was batted from the top of a skyscraper. It would take a lot longer to hit the ground than if you hit it from only 5 feet high off the ground!

81t means the ball was hit with enough force to give it an initial upward velocity of 81 feet per unit of t, as it travels forward, so that's 81 feet per second. (Depending on the angle the ball was struck, the horizontal component may be a different number.)

-16t² accounts for Earth gravity pulling the ball downward the whole time, t, the ball is in the air (the negative sign is for downward)

For 22 points, I figured you deserved a very thorough explanation.

Hope this helps!

7 0

4 years ago

A tractor, starting from a stationary position, drives down the road. It accelerates at 4 m/s2 for 10 seconds, then travels at a

chubhunter [2.5K]

Answer:

B. 1400 meters.

Step-by-step explanation:

According to the statement, there are two stages for the motion of the tractor, in which we need to find the travelled distance:

(i) Uniform accelerated motion.

$s_{i} = s_{o,i} +v_{o,i}\cdot t_{i} + \frac{1}{2}\cdot a\cdot t_{i}^{2}$ (1)

$v_{i} = v_{o,i}+a\cdot t_{i}$ (2)

Where:

$s_{o,i}$ - Initial position of the tractor, measured in meters.

$s_{i}$ - Final position of the tractor, measured in meters.

$v_{o,i}$ - Initial velocity of the tractor, measured in meters per second.

$t_{i}$ - Time, measured in seconds.

$a$ - Acceleration, measured in meters per square second.

$v_{i}$ - Final velocity of the tractor, measured in meters per second.

(ii) Uniform motion.

$s_{ii} = s_{i} + v_{i}\cdot t_{ii}$ (3)

Where:

$s_{ii}$ - Final position of the tractor, measured in meters.

$t_{ii}$ - Time, measured in seconds.

The distance covered by the tractor ( $\Delta s$ ), measured in meters, is:

$\Delta s = s_{ii}$ (4)

If we know that $a = 4\,\frac{m}{s^{2}}$ , $t_{i} = 10\,s$ , $v_{o,i} = 0\,\frac{m}{s}$ , $s_{o,i} = 0\,m$ and $t_{ii} = 30\,s$ , then distance covered by the tractor is: