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1 year ago

I need help with this Q7

Mathematics

2 answers:

Juli2301 [7.4K]1 year ago

8 0

Answer:

14.99d

Step-by-step explanation:

d represents the number of DVDs that Allie bought

Hope this helps! :)

marissa [1.9K]1 year ago

6 0

It would be 14.99 d because they aren’t saying to add it to anything they just said what represents it and d represents dvd’s hope this helps

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5.349 round to the nearest tenth

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5.4 because the 9 bumps it to 5.35.

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2 years ago

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2 years ago

One positive number is 3 more than twice another. If their product is 629, find the numbers.

Soloha48 [4]

Answer:

17,37

Step-by-step explanation:

one number = x

The positive number = 2x + 3

x * (2x+3) = 629

x*2x + x *3 = 629

2x² + 3x - 629 = 0

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2x*(x -17) + 37(x - 17) = 0

(x - 17)(2x + 37) = 0

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2 years ago

Find the missing lengths: LK=15 and KH=9, find KI and HI.

Luda [366]

Answer:

KI=11.25 and HI=6.75

Step-by-step explanation:

Consider the below figure attached with this question.

According to Pythagoras Theorem:

$base^2+perpendicular^2=hypotenuse^2$

Use Pythagoras in triangle HKL

$LH^2+KH^2=LK^2$

$(LH)^2+9^2=15^2$

$(LH)^2+81=225$

$(LH)^2=144$

Taking square root on both sides.

$LH=12$

Let length of HI be x.

LI = 12+x

Use Pythagoras theorem in ΔKLI,

$(KI)^2+15^2=(12+x)^2$

$(KI)^2+225=x^2+24x+144$

$(KI)^2=x^2+24x+144-225$

$(KI)^2=x^2+24x-81...(1)$

Use Pythagoras theorem in ΔHKI,

$(KI)^2=x^2+9^2$

$(KI)^2=x^2+81...(2)$

From (1) and (2) we get

$x^2+81=x^2+24x-81$

$24x=162$

$x=\dfrac{162}{24}=6.75$

Hence, the measure of HI is 6.75 units.

Substitute x=6.75 in equation (2).

$(KI)^2=(6.75)^2+81$

$(KI)^2=126.5625$

Taking square root on both sides.

$KI=\sqrt{126.5625}$

$KI=11.25$

Hence, the measure of KI is 11.25 units.

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3 years ago

Is the height of an equilateral triangle the same as the sides?

Hoochie [10]

No,
although all the sides are the same length on an equilateral triangle the height is calculated by a straight perpendicular line at the mid point of the base.

The sides are not perpendicular with the base and are angled outwards

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2 years ago