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Alla [95]
4 years ago
12

Which functions have real zeros at 1 and 4? Check all that apply.

Mathematics
2 answers:
ololo11 [35]4 years ago
8 0

Answer:

ED2020 its B and D

Step-by-step explanation:

erastova [34]4 years ago
5 0
f(x)=x^2+x+4=0\ \text{NO SOLUTIONS}\ :(\\\\f(x)=x^2-5x+4=x^2-4x-x+4=x(x-4)-1(x-4)\\=(x-4)(x-1)=0\iff x=4\ \vee\ x=1\ \text{CORRECT}\\\\f(x)=x^2+3x-4=x^2+4x-x-4=x(x+4)-1(x+4)\\=(x+4)(x-1)=0\iff x=-4\ \vee\ x=1\ :(

f(x)=-2x^2+10x-8=-2(x^2-5x+4)=-2(x^2-4x-x+4)=\\-2[x(x-4)-1(x-4)]=-2(x-4)(x-1)=0\iff x=4\ \vee\ x=1\ \text{CORRECT}\\\\f(x)=-4x^2-16x-1\to f(1)=-4\cdot1^2-16\cdot1-1=-4-16-1=-21\neq0\ :(


Answer:
\boxed{f(x)=x^2-5x+4\ and\ f(x)=-2x^2+10x-8}
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Answer:

(0,-63)

Step-by-step explanation:

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The Riches are ordering topsoil for their new lawn. The topsoil will be spread evenly over the yard before the grass is planted.
Simora [160]

Answer:

I think its 55.5

Step-by-step explanation

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5 0
3 years ago
I need help thank you
Liono4ka [1.6K]

Answer:

x is greater than or equal to 8.75 or 8 3/4

Step-by-step explanation:

So we first write the inequality 3 + 1.2c "is greater than or equal to sign" 13.5. Then we subtract 3, then divide both sides by 1.2 to isolate c. We get x "is greater than or equal to" 8.75.

8 0
4 years ago
Simplify $\frac{1+\sqrt{2}}{2+\sqrt{3}}$. Your solution can be converted to the form $A(1+\sqrt{B})-(\sqrt{C}+\sqrt{D})$, where
Zina [86]

Answer:

A+B+C+D = 13

Step-by-step explanation:

The given expression is:

\dfrac{1+\sqrt{2}}{2+\sqrt{3}}

We have to simply it and express it in the form of:

A(1+\sqrt{B})-(\sqrt{C}+\sqrt{D})

Multiply and divide the given expression with 2-\sqrt 3:

\dfrac{1+\sqrt{2}}{2+\sqrt{3}} \times \dfrac{2-\sqrt 3}{2-\sqrt 3}\\\Rightarrow \dfrac{(1+\sqrt{2}) \times (2-\sqrt 3)}{(2+\sqrt{3})\times (2-\sqrt 3)}\\\Rightarrow \dfrac{2+2\sqrt2-\sqrt3-\sqrt6}{2^2-(\sqrt{3})^2}\\\Rightarrow \dfrac{2+2\sqrt2-\sqrt3-\sqrt6}{4-3}\\\Rightarrow \dfrac{2(1+\sqrt2)-(\sqrt3+\sqrt6)}{1}\\\Rightarrow 2(1+\sqrt2)-(\sqrt3+\sqrt6)

It is the simplified form of given expression.

<u>Formula used: </u>

<u></u>(a+b)(a-b) = a^{2} -b^{2}<u></u>

<u></u>

<u>Comparing the simplified expression with </u>A(1+\sqrt{B})-(\sqrt{C}+\sqrt{D})<u></u>

2(1+\sqrt2)-(\sqrt3+\sqrt6)=A(1+\sqrt{B})-(\sqrt{C}+\sqrt{D})\\\Rightarrow A =2, B=2, C=3\ and\ D=6

So, value of

A+B+C+D = 2+2+3+6 = 13

8 0
4 years ago
X=____ Do the side length form a Pythagorean triple?
stira [4]

Answer:

7^2 + 11^2 = 49+121 = 170

Step-by-step explanation:

\sqrt{170} = 13.08...

NO. It is not a triple.

5 0
3 years ago
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