Help? I may have asked this question already

0=5x+3 solve equation

Sergeu [11.5K]

5x+3=0

5x=–3

x=–3/5

x=– 0.6

8 0

3 years ago

Read 2 more answers

A parabola can be drawn given a focus of (8, 6) and a directrix of x=4 Write the equation of the parabola in any form. Answer:

Alexeev081 [22]

Answer:

The equation of the parabola in vertex form is $x-6 = \frac{1}{16}\cdot (y-6)^{2}$ .

Step-by-step explanation:

Since the directrix is of the $x = a$ , then the equation of the parabola in vertex form is of the form:

$x-h = \frac{1}{4\cdot p}\cdot (y-k)^{2}$ (1)

Where:

$x$ - Dependent variable.

$y$ - Independent variable.

$p$ - Least distance between focus and directrix.

$h$ , $k$ - Coordinate of the vertex.

The least distance between focus and directrix is determined by Pythagorean Theorem:

$p = \sqrt{(8-4)^{2}+(6-6)^{2}}$

$p = 4$

Now, we determine the location of the vertex by the following vectorial formula:

$(h,k) = F(x,y) - (0.5\cdot p, 0)$ (2)

If we know that $p = 4$ and $F(x,y) = (8,6)$ , then the location of the vertex is:

$(h,k) = (8,6) -(2, 0)$

$(h,k) = (6,6)$

And the equation of the parabola in vertex form is $x-6 = \frac{1}{16}\cdot (y-6)^{2}$ .

5 0

3 years ago

Fiona is 7 years older than Gavin. Alex is 12 years younger than Gavin. If the total of their ages is 73, how old is the younges

Ymorist [56]

the youngest of them is 42

i hope this was helpful:)

3 0

3 years ago

And the cross-section perpendicular to the yaxis is a square. Set up a definite integral expressing the volume of the solid

zheka24 [161]

The volume of the cross-section perpendicular to the solid is the amount of space in the cross-section

<h3>How to set up the integral?</h3>

The question is incomplete;

So, I will give a general explanation on how to set up a definite integral for volume of a solid

Assume the solid is a cone;

Using the disk method, the integral of the volume is:

$V = \int\limits^a_b {\pi r(x)^2} \, dx$

Using the washer method, the integral of the volume is:

$V = \int\limits^a_b {\pi [R(x)^2 -r(x)^2 ]} \, dx$

Read more about volume integrals at:

brainly.com/question/18371476

4 0

2 years ago

In class, Julie was asked to create a scenario for the linear function shown. She came up with the following: .Joe planned a hik

Law Incorporation [45]

Answer:

1. Julie’s scenario doesn't match the linear function graphed, because the graphed function is f(x)=-3x+12 and must be f(x)=-5x+12

2. She has counted the slope of the line incorrect.

3. She can write f(x)=-5x+12 and draw the line with the x-intercept will be at (2.4,0) and y-intercpt ar (0,12).

Step-by-step explanation:

If Joe parked 12 miles away from the cabin and after one hour, he was still 7 miles from the cabin, then he had walked 12 - 7 = 5 miles per hour.

The initial positon of Joe is at point (0,12) (after 0 hours passed, Joe was 12 miles from the cabin). The line must pas through the point (1,7) ( after one hour, he was still 7 miles from the cabin ).

Find the slope:

$\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{7-12}{1-0}=-5$

So, the slope of the linear function should be -5 (not -3).

Then the equation of the function is

$f(x)=-5x+12$

1. Julie’s scenario doesn't match the linear function graphed, because the graphed function is f(x)=-3x+12 and must be f(x)=-5x+12

2. She has counted the slope of the line incorrect.

3. She can write f(x)=-5x+12 and draw the line with the x-intercept will be at (2.4,0) and y-intercpt ar (0,12).

5 0

4 years ago

Help? I may have asked this question already ​

Help? I may have asked this question already