Answer:
Step-by-step explanation:
![7- \sqrt[3]{2-x} =12](https://tex.z-dn.net/?f=7-%20%5Csqrt%5B3%5D%7B2-x%7D%20%3D12)
we have to just keep in mind to do the same operation to both sides of the equal sign
![7-7- \sqrt[3]{2-x} =12-7](https://tex.z-dn.net/?f=7-7-%20%5Csqrt%5B3%5D%7B2-x%7D%20%3D12-7)
; subtract 7 from both sides
![- \sqrt[3]{2-x} = 5](https://tex.z-dn.net/?f=-%20%5Csqrt%5B3%5D%7B2-x%7D%20%3D%205)
; multiply both sides by -1
![\sqrt[3]{2-x} = -5](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2-x%7D%20%3D%20-5)
; raise both sides to the power 3
2-x = (-5)³
2-x = -125 ; subtract 2 from both sides
-x = -125-2
-x =-127; multiply both sides by -1
x= 127
More information for 3/ 15 for the simplest form
Yep! They are all right! Great job, could write a bit better.... sorry
Answer:
7(3^2) + 2(3).
That equals to 7(9) + 2(3).
That equals to 63 + 6.
That finally equals to 69.
Step-by-step explanation:
