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Kazeer [188]
3 years ago
14

The function g is defined by g(x)=9k−4, where k is a constant. Find k, if the graph of g passes through the point (7,−2).

Mathematics
2 answers:
Tomtit [17]3 years ago
7 0
<span>given g(x)=9k−4 and </span><span>g passes through the point (7,−2)

substiting g(7) = 9*k - 4 = -2

so 9*k = -2 + 4 = 2

k = 2/9 or 0.22</span>
Nutka1998 [239]3 years ago
3 0

Answer: k=\dfrac{2}{9}

Step-by-step explanation:

Given : The function g is defined by g(x)=9k-4, where k is a constant.

If the graph of g passes through the point (7,−2), then at x=7 , the value of g should be -2.

So substitute x=7 then g(7)=-2.

Consider g(7)=9k-4

\Rightarrow\ -2=9k-4

Adding 4 on both sides , we get

\Rightarrow\ 9k=2

Dividing both sides  by 9 , we get

k=\dfrac{2}{9}

Hence, the value of k=\dfrac{2}{9}.

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3 years ago
A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

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