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3 years ago

The function g is defined by g(x)=9k−4, where k is a constant. Find k, if the graph of g passes through the point (7,−2).

2 answers:

7 0

<span>given g(x)=9k−4 and </span><span>g passes through the point (7,−2)

substiting g(7) = 9*k - 4 = -2

so 9*k = -2 + 4 = 2

k = 2/9 or 0.22</span>

Nutka1998 [239]3 years ago

3 0

Answer: $k=\dfrac{2}{9}$

Step-by-step explanation:

Given : The function g is defined by $g(x)=9k-4$ , where k is a constant.

If the graph of g passes through the point (7,−2), then at x=7 , the value of g should be -2.

So substitute x=7 then g(7)=-2.

Consider $g(7)=9k-4$

$\Rightarrow\ -2=9k-4$

Adding 4 on both sides , we get

$\Rightarrow\ 9k=2$

Dividing both sides by 9 , we get

$k=\dfrac{2}{9}$

Hence, the value of $k=\dfrac{2}{9}$ .

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Answer:

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Step-by-step explanation:

Let us denote the least common multiple of a and b [a,b]=m.

We want to prove that m divides n, where n is a multiple of a and b.

We suppose m does not divide n, then by the Division Theorem, there exists q and r integers such that:

(1) ... n=mq+r, where 0<r<m

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So (1) has the following form:

n=mq+r ⇒ sa=uaq+r ⇒sa-uaq=r⇒(s-uq)a=r and

n=mq+r ⇒ tb=vbq+r ⇒ tb-vbq=r⇒ (t-vq)b=r

So r is a multiple of a and b, but r<m which is a contradiction as, m is the least common multiple of a and b. So this concludes the proof.

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