A right triangles hypotenuse is the square root of both of the other side squared. The formula for this is a^2 + b^2= c^2, with c being the longest side. So 10 squared is 100, 13 squared is 169, but. 17 squared is 289. The sum of the other two sides are 269. So it doesn’t equal
That is the answer it was to long to write down
If you mean "how to write the sum", the answer is

The result of this sum is
, because you start from 2 on the number line and take 3 steps to the left (negative integers mean going left, positive integers mean going right)
Answer:
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Step-by-step explanation:
Answer:

Step-by-step explanation:
Given
![A = \left[\begin{array}{cc}-2&6\\3&5\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%266%5C%5C3%265%5Cend%7Barray%7D%5Cright%5D)
Required
Determine the determinant
For a two by two matrix, A such that:
![A = \left[\begin{array}{cc}a&b\\c&d\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D)
The determinant |A| is:

So, in
![A = \left[\begin{array}{cc}-2&6\\3&5\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%266%5C%5C3%265%5Cend%7Barray%7D%5Cright%5D)
The determinant is:


