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3 years ago

Can someone please help with the image below will give brainliest

Mathematics

1 answer:

pshichka [43]3 years ago

8 0

Answer:

Option 1.

Step-by-step explanation:

It's option 1.

You divide (b/a) by 2 then square it, then subtract this from both sides of the equation. It is the process of Completing the Square.

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if you have 678 t-shirts and you want to put the same amount of t-shirts in 4 boxes how would you do that?

KIM [24]

In order to solve this problem, you will need to use a type of operation. You can do long division which will be 678 divided 4 and it will give you 169 remainder 5.

4 0

4 years ago

Read 2 more answers

Mr. Brenton loves to take his daughter to the park to go sliding. She has to much fun. He has seven- eighths of a tank of gas. H

julia-pushkina [17]

The answer is five times
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42 divided by 8 = 5.25
but the answer has to be a whole number so the answer is 5

hope this helps :-D

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3 years ago

2 ÷ 24.42 = ? ...... . ....

Karolina [17]

Answer:

12.21

Step-by-step explanation:

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3 years ago

i was running in a marathon i was in last place then i oveer toke the second place runner what place am i now?

Ann [662]

You’re in second place

7 0

3 years ago

Read 2 more answers

One measure of an athlete’s ability is the height of his or her vertical leap. Many professional basketball players are known fo

almond37 [142]

Answer:

(1) P( $\bar X$ < 26 inches) = 0.0436

(2) P(27.5 inches < $\bar X$ < 28.5 inches) = 0.2812

Step-by-step explanation:

We are given that the mean vertical leap of all NBA players is 28 inches. Suppose the standard deviation is 7 inches and 36 NBA players are selected at random.

Firstly, Let $\bar X$ = mean vertical leap for the 36 players

Assuming the data follows normal distribution; so the z score probability distribution for sample mean is given by;

Z = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean vertical leap = 28 inches

$\sigma$ = standard deviation = 7 inches

n = sample of NBA player = 36

(1) Probability that the mean vertical leap for the 36 players will be less than 26 inches is given by = P( $\bar X$ < 26 inches)

P( $\bar X$ < 26) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{26-28}{\frac{7}{\sqrt{36} } }$ ) = P(Z < -1.71) = 1 - P(Z $\leq$ 1.71)

= 1 - 0.95637 = 0.0436

(2) Now, here sample of NBA players is 26 so n = 26.

Probability that the mean vertical leap for the 26 players will be between 27.5 and 28.5 inches is given by = P(27.5 inches < $\bar X$ < 28.5 inches) = P( $\bar X$ < 28.5 inches) - P( $\bar X$ $\leq$ 27.5 inches)

P( $\bar X$ < 28.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{28.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z < 0.36) = 0.64058 {using z table}

P( $\bar X$ $\leq$ 27.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{27.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z $\leq$ -0.36) = 1 - P(Z < 0.36)

= 1 - 0.64058 = 0.35942

Therefore, P(27.5 inches < $\bar X$ < 28.5 inches) = 0.64058 - 0.35942 = 0.2812

6 0

4 years ago