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nalin [4]
4 years ago
13

50:19

Mathematics
1 answer:
vladimir2022 [97]4 years ago
6 0

Answer:

The margin of error is multiplied by 1.41, which is 1 divided by the square root of 5.

Step-by-step explanation:

The margin of error is:

M = z*\frac{\sigma}{\sqrt{n}}

In which z is related to the confidence level, \sigma is the standard deviation of the population and n is the size of the sample.

The margin of error is inverse proportional to the square root of the sample size.

Then

Sample size n:

M = z*\frac{\sigma}{\sqrt{n}}

Modified(half the sample size):

M_{M} = z*\frac{\sigma}{\sqrt{0.5n}}

Ratio

\frac{M_{M}}{M} = \frac{z*\frac{\sigma}{\sqrt{0.5n}}}{z*\frac{\sigma}{\sqrt{n}}} = \frac{\sqrt{n}}{\sqrt{0.5n}} = \frac{\sqrt{n}}{\sqrt{0.5}*\sqrt{n}} = \frac{1}{\sqrt{0.5}} = 1.41

The margin of error is multiplied by 1.41, which is 1 divided by the square root of 5.

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