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Fed [463]
2 years ago
5

Plz help answer fast

Mathematics
1 answer:
Tems11 [23]2 years ago
3 0

Answer:

You see x is just the multiplied side of the opposite one, and you know 180 is half of 360 (full degrees). X=10 divided by 9 which is more than one, and the answer that belongs in the box is 10 divided by 9 is 180x10 and thats your answer :)

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Un olivar tiene 80 olivos. Sesenta de ellos dan, por término medio, 50 kg 4 hg 60 dag 5 g de aceitunas cada uno, y los otros vei
vlada-n [284]

Answer:

1330.808 euros

Step-by-step explanation:

Let's first calculate the total amount of kilograms,

for the first 60, we have to:

50 kg

4 hg = 0.5 kg

60 dag = 0.6

5 g = 0.005 kg

adding: 50 + 0.5 +0.6 + 0.005 = 51.105 kg per tree, but they are 60

51.105 * 60 = 3066.3

now for the other 20:

53 kg

2 hg = 0.2 kg

16 dag = 0.16

5 g = 0.005

adding: 53 + 0.2 +0.16 + 0.005 = 53.365 kg per tree, but they are 20

53,365 * 20 = 1067.3

in total it would be: 3066.3 + 1067.3 = 4133.6

they tell us that 1/5 is the quantity in liters:

4133.6 * 1/5 = 826.72 liters

so to calculate the earnings it would be:

2.65 * 826.72 - 860 = 1330.808

which means that in net earnings are 1330.808 euross

8 0
3 years ago
True or false question
Romashka [77]
The answer should be true
6 0
3 years ago
Write an equation in slope intercept form for the line that passes through (-3,-1) and
ahrayia [7]

Step-by-step explanation:

The equation is y = -x - 4.

8 0
2 years ago
Find two numbers for which the sum is 101 and the difference is 47
ANEK [815]

Answer:

74 and 27

Step-by-step explanation:

let x and y be the numbers

x + y =101........eqn 1

x - y = 47.......eqn 2

solve simultaneously

from equation 2, make x the subject

x= 47 + y........eqn 3

put eqn 3 into eqn 1

(47+y) + y = 101

47 + 2y = 101

       2y= 101 - 47

       2y=54

         y= 54/2

         y= 27

put y=27 into eqn 3

x = 47 + 27

x = 74

5 0
3 years ago
Read 2 more answers
If a random sample of size nequals=6 is taken from a​ population, what is required in order to say that the sampling distributio
goldenfox [79]

Answer:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

Step-by-step explanation:

For this case we have that the sample size is n =6

The sample man is defined as :

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And we want a normal distribution for the sample mean

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

So for this case we need to satisfy the following condition:

X_i \sim N(\mu , \sigma), i=1,2,...,n

Because if we find the parameters we got:

E(\bar X) =\frac{1}{n} \sum_{i=1}^n E(X_i) = \frac{n\mu}{n}=\mu

Var(\bar X)= \frac{1}{n^2} \sum_{i=1}^n Var(X_i) = \frac{n\sigma^2}{n^2}= \frac{\sigma^2}{n}

And the deviation would be:

Sd (\bar X) = \frac{\sigma}{\sqrt{n}}

And we satisfy the condition:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

3 0
2 years ago
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