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3 years ago

A triangular prism has a height of 6 meters and a triangular base with the following dimensions.

Mathematics

2 answers:

Novosadov [1.4K]3 years ago

4 0

The value of B is 48m. squared
This is because the formula for a triangle is (length×hight÷2)

So in this case, multiply 16 and 6 to get 96. Then divide 96 by 2 to get 48m. squared

Reptile [31]3 years ago

4 0

Answer: The correct option is (B) 48 m².

Step-by-step explanation: Given that a triangular prism has a height of 6 meters and a triangular base with the dimensions as shown in the figure.

We are to find the value of B, the area of the base of the prism.

As shown in the figure,

the base of the prism is a triangle with base length 16 m and height 6 m.

We know that

the area of a triangle with base b units and height h units

$A=\dfrac{1}{2}\times b\times h.$

In the given triangular base of the prism, we have

b = 16 m and h = 6 m.

Therefore, the area of the base will be

$B=\dfrac{1}{2}\times b\times h=\dfrac{1}{2}\times 16\times 6=48~\textup{m}^2.$

Thus, the required value of B is 48 m².

Option (B) is CORRECT.

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Factor x^2-6x+9 <<< Need Help?

Triss [41]

Hey!!
So to factor it, you want to see what 2 numbers will multiply and make 9 and what 2 numbers will add and make -6.
so 9 and 1 and -9 and -1 make 9 but they dont make -6.
3 and 3 and -3 and -3 make 9, but we need to see which one makes -6. that would be -3 and -3
so the answer is (x-3)(x-3)

you can foil to make sure.
x * x is x^2
-3*x=-3x
-3*x=-3x
-3x-3x = -6x
-3*-3 is 9
so it is x^2-6x+9 which makes the original equation

Hope this helps!

8 0

3 years ago

Read 2 more answers

Jayden and Sheridan both tried to find the missing side of the right triangle. A right triangle is shown. One leg is labeled as

stellarik [79]

Answer:

Sheridan's Work is correct

Step-by-step explanation:

we know that

The lengths side of a right triangle must satisfy the Pythagoras Theorem

$c^{2}=a^{2}+b^{2}$

where

a and b are the legs

c is the hypotenuse (the greater side)

In this problem

Let

$a=7\ cm\\c=13\ cm$

substitute

$13^{2}=7^{2}+b^{2}$

Solve for b

$169=49+b^{2}$

$b^{2}=169-49$

$b^{2}=120$

$b=\sqrt{120}\ cm$

$b=10.95\ cm$

we have that

<em>Jayden's Work</em>

$a^{2}+b^{2}=c^{2}$

$a=7\ cm\\b=13\ cm$

substitute and solve for c

$7^{2}+13^{2}=c^{2}$

$49+169=c^{2}$

$218=c^{2}$

$c=\sqrt{218}\ cm$

$c=14.76\ cm$

Jayden's Work is incorrect, because the missing side is not the hypotenuse of the right triangle

<em>Sheridan's Work</em>

$a^{2}+b^{2}=c^{2}$

$a=7\ cm\\c=13\ cm$

substitute

$7^{2}+b^{2}=13^{2}$

Solve for b

$49+b^{2}=169$

$b^{2}=169-49$

$b^{2}=120$

$b=\sqrt{120}\ cm$

$b=10.95\ cm$

therefore

Sheridan's Work is correct

6 0

3 years ago

Read 2 more answers

7 – (5t – 13) = –25 HELP NO TROLLING ALSO PLS EXPLAIN HOW U GOT IT TY !

aleksklad [387]

The answer would be 9 you would add the 13 and 7 then have 20-5t=-25 then subtract 20 from 25 then you would have -5=-45 which is 9

6 0

3 years ago

Of the 36 students in the environmental club, 15 or boys and 21 are girls. The president of the club wants to add more boys so t

schepotkina [342]

Because 50% of something means half (because 100-50=50), he would have to make the number of girls and boys equal. Since there are 21 girls, he has to make it so there are also 21 boys.
So, if we know that 21-15=6, this means he would have to add 6 boys to the club if he wants the girls and boys equal.

4 0

3 years ago

A student bought 3 shirts at $12.25 each and 2 pairs of pants at $25.50 each. How much money

4vir4ik [10]

Answer: 87.75

Step-by-step explanation:

Multiply 12.25 times 3 because the student bought 3 shirts

Then multiply 25.50 times 2 because the student bought two pairs of pants

Then add up both your multiplication together and you will get 87.75

3 0

3 years ago