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diamong [38]
2 years ago
8

For a triangle which two points of concurrence could be located outside the triangle

Mathematics
2 answers:
Harrizon [31]2 years ago
8 0

Answer:

Circumcentre and Orthocentre

Step-by-step explanation:

There is not always the circumcentre of a triangle inside the triangle. For the triangle, therefore, the othorcentre and the circumcentre are two points of rivalry which can be found outside of the triangle.

I am joyous to assist you anytime.

borishaifa [10]2 years ago
5 0
The incentre of a triangle is the intersection of all the angle bisectors of the triangle. It is always located inside the triangle.

The centroid of a triangle is the intersection of the lines joining the midpoint of each side of the triangle with the opposite vertex. I always lies within the triangle.

The orthocenter of a triangle <span>is the point where all three altitudes of the </span>triangle<span> intersect. An </span>altitude<span> is a line which passes through a vertex of the </span>triangle<span> and is perpendicular to the opposite side. The othorcenter of the triangle does not alway lie inside the triangle.

The</span> circumcenter of a triangle<span> is the point where the perpendicular bisectors of a </span>triangle<span> intersect. The </span>circumcenter<span> is also the center of the </span>triangle's circumcircle<span> - the circle that passes through all three of the </span>triangle's<span> vertices. The circumcentre of a triangle is not always located inside the triangle.

Therefore, f</span><span>or a triangle, the two points of concurrence which could be located outside the triangle are the othorcenter and the circumcenter.</span>
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Answer:

32 years old.

Step-by-step explanation:

13 times 2 is 26, and 6 added to 26 is 32.

I hope this helps, have a nice day.

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Sergio [31]

Answer:

The 99% confidence interval would be given (11.448;14.152).

Step-by-step explanation:

1) Important concepts and notation

A confidence interval for a mean "gives us a range of plausible values for the population mean. If a confidence interval does not include a particular value, we can say that it is not likely that the particular value is the true population mean"

s=16.6 represent the sample deviation

\bar X=12.8 represent the sample mean

n =1003 is the sample size selected

Confidence =99% or 0.99

\alpha=1-0.99=0.01 represent the significance level.

2) Solution to the problem

The confidence interval for the mean would be given by this formula

\bar X \pm z_{\alpha/2} \frac{s}{\sqrt{n}}

We can use a z quantile instead of t since the sample size is large enough.

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

12.8 - 2.58 \frac{16.6}{\sqrt{1003}}=11.448

12.8 + 2.58 \frac{16.6}{\sqrt{1003}} =14.152

And the 99% confidence interval would be given (11.448;14.152).

We are confident that about 11 to 14 are the number of books that the people had read on the last year on average, at 1% of significance.

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Step-by-step explanation:

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