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VladimirAG [237]
3 years ago
13

A large helium balloon is tethered to the ground by two cables. One cable is 100 feet long and forms an 80 degree angle with the

ground. The second cable forms a 40 degree angle with the ground. How long is the second cable to the nearest foot? Also, how far apart are the tethers, rounded to the nearest foot?

Mathematics
1 answer:
liraira [26]3 years ago
6 0

Hey there :)

Answer attached in image. Check!

~Benjemin360

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Solve each equation. If exact roots cannot be found, state the consecutive integers between which the roots are located.
vodomira [7]

Answer:

x=2

Step-by-step explanation:

x^2+10x+24=0

12x=24=0

12x=24

x=2

My math is rusty so this may not be the right answer.

3 0
3 years ago
Can someone please help me ASAP.....
tester [92]

We have to start with a number x, compute f(x), and then use this result as input for g(x)

When you give x as input to f, it returns -x^2-1:

x\mapsto f(x)-x^2-1

Now, g(x)=x+5 simply means that g will return its input plus five.

In this case, the input is f(x), so we have

g(f(x))=f(x)+5 = -x^2-1+5=-x^2+4

5 0
4 years ago
Help me with this hard decimals Decimals is 3.5/100
zubka84 [21]
Just divide 3.5 with 100 so it would be 0.035
8 0
3 years ago
Read 2 more answers
Mrs. Laura is between 50 and 80. If you divide her age by 9, the remainder is 1. If you divide by 4, the remainder is 1. How old
Mila [183]

Answer:

73 y/o

Step-by-step explanation:

Multiples of 9   between 50 and 80:

54    63     72     now add 1

55    64     73     now divide by 4 to find which has remainder of 1

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3 0
2 years ago
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Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin<0
Gre4nikov [31]

Answer:

Using trigonometric ratio:

\sec \theta = \frac{1}{\cos \theta}

\tan \theta = \frac{\sin \theta}{\cos \theta}

From the given statement:

\cos \theta = -\frac{4}{5} and sin < 0

⇒\theta lies in the 3rd quadrant.

then;

\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}

Using trigonometry identities:

\sin \theta = \pm \sqrt{1-\cos^2 \theta}

Substitute the given values we have;

\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}

Since, sin < 0

⇒\sin \theta = -\frac{3}{5}

now, find \tan \theta:

\tan \theta = \frac{\sin \theta}{\cos \theta}

Substitute the given values we have;

\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}

Therefore, the exact value of:

(a)

\sec \theta =-\frac{5}{4}

(b)

\tan \theta= \frac{3}{4}

7 0
3 years ago
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