Answer:
The flight was 137.45 miles farther than the direct path.
(make slight changes if directions were given on how to round. This is to the nearest hundredth)
Step-by-step explanation:
Use the Law of Cosines.
c^2=
a^2+b^2-2abcosC
You know two sides and the angle in between. The Law of Cosines will give us the third side.
The third side is the direct path of the airplane. We'll add the two other given sides to find the detour route that they took instead.
Then subtract the smaller number (direct route) from the actual route. See image.
Answer:
$3
Step-by-step explanation:
Given data
Let the cost of drinks be x
and the cost of hotdogs be y
so
3x+4y=15-------1
also
3x+y= 10.5------2
solve 1 and 2
3x+4y=15
-3x+y= 10.5
3y= 4.5
divide both sides by 3
y= 4.5/3
y= $1.5
Put y= 1.5 in 1
3x+4(1.5)=15
3x+6= 15
3x=15-6
3x= 9
x= 9/3
x= $3
Hence the cost of a drink is $3
Answer:
I think this is the correct solution
Answer:
Neither
Step-by-step explanation:
Answer: a - 4.512 hours
b - 1.94 hours
Step-by-step explanation:
Given,
a) A(t) = 10 (0.7)^t
To determine when 2mg is left in the body
We would have,
A(t) = 2, therefore
2 = 10(0.7)^t
0.7^t =2÷10
0.7^t = 0.2
Take the log of both sides,
Log (0.7)^t = log 0.2
t log 0.7 = log 0.2
t = log 0.2/ 0.7
t = 4.512 hours
Thus it will take 4.512 hours for 2mg to be left in the body.
b) Half life
Let A(t) = 1/2 A(0)
Thus,
1/2 A(0) = A(0)0.7^t
Divide both sides by A(0)
1/2 = 0.7^t
0.7^t = 0.5
Take log of both sides
Log 0.7^t = log 0.5
t log 0.7 = log 0.5
t = log 0.5/log 0.7
t = 1.94 hours
Therefore, the half life of the drug is 1.94 hours
