Question

What are the roots of the quadratic equation below? 2x^2 – 5x-1=0

Answer 1

Answer:

$x_1=\frac{5+\sqrt{33}}{4}\approx2.6861\\ \\x_2=\frac{5-\sqrt{33}}{4}\approx-0.1861$

Step-by-step explanation:

$2x^2-5x-1=0\\\\x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\ \\x=\frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-1)}}{2(2)}\\ \\x=\frac{5\pm\sqrt{25+8}}{4}\\ \\x=\frac{5\pm\sqrt{33}}{4}\\ \\x_1=\frac{5+\sqrt{33}}{4}\approx2.6861\\ \\x_2=\frac{5-\sqrt{33}}{4}\approx-0.1861$