All categories

2 years ago

Factor the following: 64x2−144xy+81y2

Mathematics

1 answer:

maks197457 [2]2 years ago

6 0

Answer:

(8x - 9y)2

Step-by-step explanation:

64x2−144xy+81y2

Equation at the end of step 1:

((64 • (x2)) - 144xy) + 34y2

The Equation at the end of step 2:

(26x2 - 144xy) + 34y2

Step 3:

(8x - 9y)2

Answer:

(8x - 9y)2

You might be interested in

Which of the following is the best approximation of the area of a circle whose diameter is 14 feet?

Ray Of Light [21]

Area of a circle is pi x r^2

R = d/2 = 14.2 = 7

Area = 3.14 x 7^2
Area = 3.14 x 49
Area = 153.86 round to 154

Answer is 154 square feet.

8 0

3 years ago

A researcher wishes to find out shearer givinh a student 1 million in cash will improve or ruin the students grades in school

arlik [135]

Need more info please.

6 0

3 years ago

i see two things at the mall one shirt is 32$ and is 70% off and the 2nd shirt is 33$ and is 71% percent off which is a better d

Lemur [1.5K]

They would be an equal price

8 0

3 years ago

Two times the greater of two consecutive integers is 9 less than three times the lesser integer. What are the integers?

lara [203]

Answer:

11 and 12

Step-by-step explanation:

x=smaller

y=larger

2y=3x-9 x+1=y

2(x+1)=3x-9

2x+2=3x-9

11=x

11+1=y

12=y

3 0

3 years ago

1.) What is the equation of the path of firework #1? Write your equation in general form.

valina [46]

1. I'm assumig that the paths are perfect parabolas

this means that their general forms can be written in $y=ax^2+bx+c$

it's easier to find vertex form first then expand to get general form

vertex form is $y=a(x-h)^2+k$ where the vertex is (h,k) and a is a constant

firework #1

vertex is (10,50), so (h,k)=(10,50) and h=10, k=50

$h_1=a(t-10)^2+50$

to find the value of $a$ , subsitute another point

(0,0)

$0=a(0-10)^2+50)$

$0=100a+50$

$a=\frac{-1}{2}$

so the equation in vertex form is $h_1=\frac{-1}{2}(t-10)^2+50$

expand to get general form

$h_1=\frac{-1}{2}(t^2-20t+100)+50$

$h_1=\frac{-1}{2}t^2+10t-50+50$

$h_1=\frac{-1}{2}t^2+10t$

same as last time

vertex is (10,72) so (h,k)=(10,72) so h=10 and k=72

equation is $h_2=a(t-10)^2+72$

find $a$

use another point

(0,22)

$22=a(0-10)^2+72$

$22=100a+72$

$-50=100a$

$a=\frac{-1}{2}$

so the equation in vertex form is $h_2=\frac{-1}{2}(t-10)^2+72$

range is the numbers that h is allowed to be

think about what h represents. it represents the height of the rocket

from the graph, we can see that the lowest possible height is 0yd and the highest height is 50yd

so range is 0 to 50 or 0≤h≤50

domain is the numbers that t is allowed to be

think about what t represents. it represents how long the rocket has been flying

it will stop flying when it hits the ground or at t=20

it starts flying at t=0

so domain is from 0 to 20 or 0≤t≤20

3 0

3 years ago