All categories

2 years ago

3) A semicircle is attached to the side of a rectangle as shown.

Mathematics

2 answers:

mojhsa [17]2 years ago

5 0

Answer:

Option C $122.1\ cm^{2}$

Step-by-step explanation:

we know that

The area of the figure is equal to the area of a rectangle plus the area of semicircle

Step 1

Find the area of the rectangle

The area of the rectangle is equal to

$A=bh$

we have

$b=18\ cm$

$h=6\ cm$

substitute

$A=18*6=108\ cm^{2}$

Step 2

Find the area of semicircle

The area of semicircle is equal to

$A=\frac{1}{2}\pi r^{2}$

we have

$r=6/2=3\ m$

substitute

$A=\frac{1}{2}(3.14)(3^{2})=14.1\ cm^{2}$

Step 3

Find the area of the figure

$108\ cm^{2}+14.1\ cm^{2}=122.1\ cm^{2}$

m_a_m_a [10]2 years ago

3 0

Rectangle = 18 x 6 = 108
Circle: 3.14 x (3)^2 = 3.14 x 9 = 28.26
<span>semicircle: 28.26 / 2 = 14.13
</span>
108 + 14.13 = 122.13

answer
122.13 cm^2

You might be interested in

What is the measure of angle A?

fgiga [73]

Answer:

∠A=65º

Step-by-step explanation:

A angle of a line is 180º, so we can say that angle ABC=(180-6x)º
The interior angkes of a triangle is 180º, so (x+40)º+(3x+10)º+(180-6x)º=180º
Remove parenthesis, x+40+3x+10+180-6x=180
Combine like terms, -2x+230=180
Subtract 180, -2x=-50
Divide by -2, so x=25

Now:

∠CAB=(25+40)º=65º
∠ABC=[180-6(25)]º=30º
∠BCA=[3(25)+10]=85º

5 0

2 years ago

A survey of 80 students found that 24 students both play in the band and play a sport. But 22 students are not in band and do no

Tatiana [17]

Answer:

Option D.

Step-by-step explanation:

Not everyone who plays band is going to be in sports or vise versa

Hope this helped!

6 0

3 years ago

If someone could help!

ad-work [718]

Step-by-step explanation:

This time round, use SOH method (Sin angle = Opposite/Hypotenuse)

given Opposite = 7

Hypotenuse = 10

$\sin(x) = \frac{opposite}{hypotenuse} \\ \sin(x) = \frac{7}{10} \\ x = {sin}^{ - 1} ( \frac{7}{10} ) \\ = 44.4deg(nearest \: tenth)$

4 0

3 years ago

Given A(-2, 5) and B(13, -7), find the midpoint of AB.

Dmitrij [34]

Answer:

The mid-point is (9,-9/2)

Step-by-step explanation:

You would use the mid-point formula for this

$(\frac{x_{2} +x_{1} }{2} , \frac{y_{2}+y_{1} }{2} )$

if you plug that in it is ( $\frac{13-2}{2}, \frac{-7+5}{2}$ )

resulting in (11/2,-2/2) = (11/2,-1)

4 0

1 year ago

What is the area of a square with a side of 8x^7 y^3

sukhopar [10]

Area of a square with side s is $\sf{s^2}$

In your question, the side or s is: $\sf{8x^7y^3}$

And so the area of a square with that side length would be:

$\sf{(8x^7y^3)^2}$

And using this formula: $\sf{(a^b)^c =a^{b\times c}}$

We get that the area is:

$\sf{(8x^7y^3)^2 = 8^2 x^{7\times 2} y^{3\times 2}}$

And simplifying that we get the final answer as:

$\huge{\boxed{\bf{Area=64x^{14}y^{6}}}}$

4 0

3 years ago