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Eduardwww [97]
2 years ago
14

A store has a 20% off sale on pants. With this discount, the price of one pair of pants before tax is $15.20.

Mathematics
2 answers:
algol132 years ago
5 0

Answer:

19$

Step-by-step explanation:

Because 19$ 20% off=15.20 and you added taxes]

Have a great day :}

Anastaziya [24]2 years ago
5 0

Answer:

$21.16

Step-by-step explanation:

To calculate the original price of a discounted or sale item, you need to know the sale price and the discount percentage. The calculations include a simple formula that divides the sale price by the result of 1 minus the discount in percentage form.

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If $1,000 is invested at 16% interest, compounded annually,
Harrizon [31]

Answer:

equation; P=A(1+r/n)^nt

P=principal amount

A=value of investment

r= interest rate in decimals

n=number of times compounded

t=time in years

P=1000(1+0.16/12)^12(5)= $2213.8 rounded

Step-by-step explanation:

8 0
3 years ago
Use the Distributive Property to solve the equation.
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Answer:

x = -6

Step-by-step explanation:

-5(x + 3) = 15

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-5x -15 =15

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-5x-15+15 =15+15

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3 years ago
What is 14 divided by 7/8
Sliva [168]

Answer:

16

Step-by-step explanation:

You have: 14 / (7/8)

To divide by fractions, all you have to do is take the reciprocal of the second number, aka flip it

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4 0
3 years ago
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3 years ago
Find and simplify each of the following for
WINSTONCH [101]

Answer:

(A) f(x + h) = 4x² + 8xh + 4h² - 6x - 6h + 6

(B) f(x + h) - f(x) = 8xh + 4h² - 6h

(C) \frac{f(x+h)-f(x)}{h}=8x+4h-6

Step-by-step explanation:

* Lets explain how to solve the problem

- The function f(x) = 4x² - 6x + 6

- To find f(x + h) substitute x in the function by (x + h)

∵ f(x) = 4x² - 6x + 6

∴ f(x + h) = 4(x + h)² - 6(x + h) + 6

- Lets simplify 4(x + h)²

∵ (x + h)² = (x)(x) + 2(x)(h) + (h)(h) = x² + 2xh + h²

∴ 4(x + h)² = 4(x² + 2xh + h²) = 4x² + 8xh + 4h²

- Lets simplify 6(x + h)

∵ 6(x + h) = 6(x) + 6(h)

∴ 6(x + h) = 6x + 6h

∴ f(x + h) = 4x² + 8xh + 4h² - (6x + 6h) + 6

- Remember (-)(+) = (-)

∴ f(x + h) = 4x² + 8xh + 4h² - 6x - 6h + 6

* (A) f(x + h) = 4x² + 8xh + 4h² - 6x - 6h + 6

- Lets find f(x + h) - f(x)

∵ f(x + h) = 4x² + 8xh + 4h² - 6x - 6h + 6

∵ f(x) = 4x² - 6x + 6

∴ f(x + h) - f(x) = 4x² + 8xh + 4h² - 6x - 6h + 6 - (4x² - 6x + 6)

- Remember (-)(-) = (+)

∴ f(x + h) - f(x) = 4x² + 8xh + 4h² - 6x - 6h + 6 - 4x² + 6x - 6

- Simplify by adding the like terms

∴ f(x + h) - f(x) = (4x² - 4x²) + 8xh + 4h² + (- 6x + 6x) - 6h + (6 - 6)

∴ f(x + h) - f(x) = 8xh + 4h² - 6h

* (B) f(x + h) - f(x) = 8xh + 4h² - 6h

- Lets find \frac{f(x+h)-f(x)}{h}

∵ f(x + h) - f(x) = 8xh + 4h² - 6h

∴ \frac{f(x+h)-f(x)}{h}=\frac{8xh + 4h^{2}-6h}{h}

- Simplify by separate the three terms

∴ \frac{f(x+h)-f(x)}{h}=\frac{8xh}{h}+\frac{4h^{2} }{h}-\frac{6h}{h}

∴ \frac{f(x+h)-f(x)}{h}=8x+4h-6

* (C) \frac{f(x+h)-f(x)}{h}=8x+4h-6

4 0
3 years ago
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