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yarga [219]
2 years ago
15

At a pizza party, Edgar and his friends drank 2 9/10 bottles of lemon-lime soda and 2 1/4

Mathematics
1 answer:
GuDViN [60]2 years ago
7 0
All together they drank 5.15 bottles of soda.
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Find x, y and z.
emmasim [6.3K]

Answer:

<u>The values for x = 56, for y = 28 and z = 64</u>

Step-by-step explanation:

1. Let's review the information given for answering the question correctly:

∠2y° and ∠56°are alternate interior angles

∠x °and ∠2y° are alternate interior angles

<u>2. . Let's find the values of x, y and z.</u>

2y = 56

<u>y = 28</u>

Therefore,

∠x ° = ∠2y°

∠x ° = ∠56°

<u>x = 56 </u>

Let's recall that all the interior angles of a triangle will always add up to 180°, thus:

∠z° = 180 - 60 - 56

∠z° = 180 - 116

<u>∠z° = 64°</u>

<u>z = 64</u>

8 0
4 years ago
Given the function y=log3(x+2)-2. List the transformations
slava [35]

Answer:

Exponential transformation.

Step-by-step explanation:

y = log_3 (x + 3) - 2

To transform this into exponential, we have:

Adding 2 to both sides

y + 2 = log_3 (x + 3)

3^(y + 2) = x + 3

x = 3^(y + 2) - 3

4 0
3 years ago
A middle school has 600 students and 34% of them are in eighth grade 1/4 of eighth graders walk to school how many eighth-grade
Nonamiya [84]
You have to find how many kids are in eighth grade so you would multiply 34x6 and get 204 then you decide that by 1/4 and you get 51
5 0
3 years ago
ASAP NEED ANSWERS FOR BOTH QUESTIONS PLEASE :)
Nostrana [21]
Answer; 8inch, 4x larger
4 0
4 years ago
If 1200 cm2 of material is available to make a box with a square base and an open top, find the largest possible volume of the b
Colt1911 [192]

Answer:

The largest possible volume V is ;

V = l^2 × h

V = 20^2 × 10 = 4000cm^3

Step-by-step explanation:

Given

Volume of a box = length × breadth × height= l×b×h

In this case the box have a square base. i.e l=b

Volume V = l^2 × h

The surface area of a square box

S = 2(lb+lh+bh)

S = 2(l^2 + lh + lh) since l=b

S = 2(l^2 + 2lh)

Given that the box is open top.

S = l^2 + 4lh

And Surface Area of the box is 1200cm^2

1200 = l^2 + 4lh ....1

Making h the subject of formula

h = (1200 - l^2)/4l .....2

Volume is given as

V = l^2 × h

V = l^2 ×(1200 - l^2)/4l

V = (1200l - l^3)/4

the maximum point is at dV/dl = 0

dV/dl = (1200 - 3l^2)/4

dV/dl = (1200 - 3l^2)/4 = 0

3l^2= 1200

l^2 = 1200/3 = 400

l = √400

I = 20cm

Since,

h = (1200 - l^2)/4l

h = (1200 - 20^2)/4×20

h = (800)/80

h = 10cm

The largest possible volume V is ;

V = l^2 × h

V = 20^2 × 10 = 4000cm^3

4 0
3 years ago
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