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3 years ago

For the polynomial below, what is the coefficient of the term with the power of 3?

Mathematics

2 answers:

Maru [420]3 years ago

6 0

Answer:

B = 1

Step-by-step explanation:

this is becus we don't write 1 as a coefficient it's there but in an invisible form

anyone who make the one visible is considered an amateur

iris [78.8K]3 years ago

3 0

Answer:

Option B

Step-by-step explanation:

x^3

Coefficient = 1

Option B

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Help me pls and dont guess

BARSIC [14]

Answer:

Step-by-step explanation:

3 1/2 times -(4/5)

First multiply 3 1/2 and -(4/5)=2 4/5

6 0

3 years ago

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Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th

trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

t = 20: 999 fishes

t = 30: 1168 fishes

(c)

$P(\infty) = 1200$

Step-by-step explanation:

Given

$P(t) =\frac{d}{1+ke^-{ct}}$

$d = 1200\\k = 11\\c=0.2$

Solving (a): Fishes at t = 0

This gives:

$P(0) =\frac{1200}{1+11*e^-{0.2*0}}$

$P(0) =\frac{1200}{1+11*e^-{0}}$

$P(0) =\frac{1200}{1+11*1}$

$P(0) =\frac{1200}{1+11}$

$P(0) =\frac{1200}{12}$

$P(0) = 100$

Solving (a): Fishes at t = 10, 20, 30

$t = 10$

$P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483$

$t = 20$

$P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999$

$t = 30$

$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

So:

The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

5 0

3 years ago

henry has 68 miles to destination after 45 minutes and 51.5 miles to destination after 71 minutes of driving. How many miles to

Airida [17]

Let d represent the distance of the destination from the starting point.

After 45 min, Henry has already driven d-68 miles. After 71 min., he has already driven d-51.5 miles.

So we have 2 points on a straight line:

(45,d-68) and (71,d-51.5). Let's find the slope of the line thru these 2 points:

d-51.5 - (d-68) 16.5 miles
slope of line = m = ----------------------- = ------------------
71 - 45 26 min

Thus, the slope, m, is m = 0.635 miles/min

The distance to his destination would be d - (0.635 miles/min)(79 min), or

d - 50.135 miles. We don't know how far his destination is from his starting point, so represent that by "d."

After 45 minutes: Henry has d - 68 miles to go;

After 71 minutes, he has d - 51.5 miles to go; and

After 79 minutes, he has d - x miles to go. We need to find x.

Actually, much of this is unnecessary. Assuming that Henry's speed is 0.635 miles/ min, and knowing that there are 8 minutes between 71 and 79 minutes, we can figure that the distance traveled during those 8 minutes is

(0.635 miles/min)(8 min) = 5.08 miles. Subtracting thix from 51.5 miles, we conclude that after 79 minutes, Henry has (51.5-5.08), or 46.42, miles left before he reaches his destination.

7 0

3 years ago

Below is the graph of y=b^x. Find b.

omeli [17]

Y = <span>b^x

when x = 1
y = b^1
y = b

Therefore, the value of b is the same as the value of y when x =1
From the graph,
When x = 1, y = 0.5
Therefore, b = 0.5

To confirm this

From the graph,

When x = -1, y = 2
Since </span>y = b^x<span>
2 = </span>b^-1
2 = 1/b
2b = 1
b = 0.5

When x = -2, y = 4
Since y = b^x
4 = b^-2
4 = 1/(b^2)
b^2 = 1/4
b = √(1/4)
b = 1/2
b = 0.5

Therefore, it is conformed that b = 0.5

5 0

3 years ago

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F(x)= (x+9x2- 9x +15

Oduvanchick [21]

Answer:

10x+15

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers