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alexira [117]
3 years ago
5

This is precalculus, please do not answer if you do not understand

Mathematics
1 answer:
Degger [83]3 years ago
6 0
2r-3
4 should be it, im sorry if its wrong!

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Given a parent function y=x^3, write a function with the following transformations: right 3, up 2, dilated by a factor of 1/2.
ser-zykov [4K]

Answer:

h(x) = (1/2)(x - 3)^2 + 2

Step-by-step explanation:

Start with y = x^3.

Multiply x^3 by the dilation factor (1/2); this compresses the graph vertically.

Next, replace the x in x^3 with (x - 3).  This shifts the graph 3 units to the right.

Last, starting with your g(x) = (1/2)(x - 3)^2, add 2

You will end up with h(x) = (1/2)(x - 3)^2 + 2.

7 0
3 years ago
What is the range of g(x)?
Jlenok [28]

Answer:

The function g(x) is defined for all real numbers x. The maximum value of the range is 4. The maximum value of the domain is 3. The range of g(x) is {y| –1 < y ≤ 4}.

Step-by-step explanation:

i don't know what your question is exactly but hope this helps.

8 0
3 years ago
What is the value of 15/4 divided by 5/8
fiasKO [112]
Answer: 6

Hope this helps!
4 0
3 years ago
Read 2 more answers
Let g(x, y) = cos(x + 2y). (a) Evaluate g(2, -1). (b) Find the domain of g. (c) Find the range of g. 1. Find and sketch the doma
skelet666 [1.2K]

Not going to do (1), (2), (3) since they are implicit from (a) and (b) and require graphs (which aren't supported on brainly).

We have g(x,y)=\cos(x+2y), that means, if plug in x=2,y=-1 we get g(2,-1)=\cos(2+2(-1))=\cos(0)=\boxed{1}.

Doman of cosine is x\in[0,1].

Hope this helps.

4 0
3 years ago
□+□+□=30<br> Fill in the boxes using 1,3,5,7,9,11,13,15<br> You can also repeat the number?
adelina 88 [10]

It is impossible to get the result of 30 using just odd numbers in the blanks.

Using factorials, we get  3! + 11 + 13 = 30 or 3! + 9 + 15 = 30

<em><u>Solution:</u></em>

----- + ------ + ------- = 30

We have to fill with numbers 1, 3, 5, 7, 9, 11, 13, 15 to get 30

We can also repeat the number

Given are the set odd numbers like 1, 3, 5, 7, 9, 11, 13, 15

We need three numbers to fill in the box to get 30

When three odd numbers are added, it results in odd number

But we should get 30, which is a even number

So it is impossible to get the result of 30 using just odd numbers in the blanks.

<em><u>Using tricks, some of solutions are:</u></em>

We can use factorial

3! + 9 + 15 = 6 + 9 + 15 = 30

Or

3! + 11 + 13

So, 6 + 11 + 13 = 30

5 0
3 years ago
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