The probability of that occurring is 0%. There are 6 sides in a typical dice, which means the probability of rolling a 2 is 1/6th. (1/6)^1000 will give you the probability of rolling a 2 exactly 1000 times. (1/6)^1000 equates to 0%.
Subtracting 3x^4+9x^3+3x^2 from the divided and bringing down 13x.
1) 2x + 3 = 2x + 3
This works because if you solve it, you will get either x = x or 3 = 3 which are always true, so x, can have an infinite number of solutions
2) 3(x + 4) = 3x + 11
This has no solution because if you solve it, you're gonna get 12 = 11 and that is NEVER true. Whatever x is, 11 cannot equal 12!
Answer:
3x-1
Step-by-step explanation:
3x^2+2x-5=3x-1 x1-25
If it needs to be a rectangle, then the rectangle with the smallest perimeter for
a given area is the square. He needs 32 feet of fence, and should fence off a
square that's 8 x 8 .
But if he's willing to go to the trouble, the perimeter of a circle with the same area
is even less than the square.
A = (pi) (R²)
R = √(64/pi).
Circumference = (2 pi) (R) = 2 pi √(64/pi) = √(256 pi) = 28.359 (rounded).
That's 11.4% less fence to buy, for a circular run.
But on the other hand, what have you got against the dog ? One of
the two main purposes of a dog run is to give the dog a place to <u>run</u>.
Minimizing the perimeter also minimizes the distance where he can get
up some speed and run in a straight line ... freeing up his hips, clearing
the cobwebs from his brain, smelling the air, keeping his claws nice and
worn down. With the emotional well-being of the dog in mind, I'd expect
you'd want to give him the <u>maximum</u> possible straight route inside the
run, which, unfortunately, also maximizes the amount of fence that Malcolm
has to provide.
But I digress. The math is done. The question is answered.
This case is closed.
