Answer:
The androecium is the sum of all the male reproductive organs, while the gynoecium is the sum of the female reproductive organs.
and If all four whorls are present, the flower is described as complete. If any of the four parts is missing, the flower is known as incomplete.
Answer:
All of the F1 progeny would be wild-type.
If the two mutations are in different genes, then we expect complementation to occur (each mutant strain provides a functional copy of the gene that is defective in the other strain) and wild-type progeny to be produced
Answer:
The probability that their first child will have long fingers is 20%
Explanation:
<u>Available data</u>:
- long fingers are inherited with 80% penetrance
- L represents the dominant allele for short fingers
- l represents the recessive allele for long fingers
Cross) Two people heterozygous for long fingers mate
Ll x Ll
Gametes) 1/2 L 1/2l 1/2L 1/2l
Punnet Square)
L l
L LL Ll
l Ll ll
F1) 25% or 1/4 LL
50% or 1/2 Ll
25% or 1/4 ll
Long fingers are inherited with 80% penetrance, which means that 80% is the proportion of the population that expresses the phenotype long fingers. Hence, the probability that the first child in this cross will have long fingers is:
100% ------- 80%
25% -------- X = 20%
It depends on if it is an aerobic or anaerobic process
Answer:
The correct answer is - 2 type A : 1 type AB : 1 type B
Explanation:
The pattern of the inheritance in the ABO blood group system is the example of the multiple alleles and codominance. There are three alleles in this sytem that determines what blood group would be in an indvidual that are; IA, IB, and IO. The allele IO is a recessive allele to both IA, and IB alleles whereas IA and IB are show codominance when present in heterzygous condition.
Genotype of a person with “A” blood group can be IA
IO or IA
IA but as it is given that the mother of the male with A bglood group is O blood group which means there must be a IO allele would be present in the male too so the genotype would be IAIO.
The genotype of AB blood group mother would be IAIB as shows codominance. so the cross between these woulde be as follows:
IA
IO x IA
IB
Gametes :
IA IO
, and IA IB
IA IO
IA IAIA IAIO
IB IAIB IBIO
phenotypic ratio = 2 A group : 1 AB group : 1 B group
