Question

When 2. 0 m aqueous solutions of sodium bicarbonate and hydrochloric acid react, it produces carbon dioxide, water and sodium chloride. Calculate the number of moles of carbon dioxide formed if 31. 6 ml of sodium bicarbonate reacts with excess hydrochloric acid.

Answer 1

The number of mole of carbon dioxide, CO₂ formed from the reaction is 0.0632 mole.

How to determine the mole of NaHCO₃

• Molarity of NaHCO₃ = 2 M
• Volume = 31.6 mL = 31.6 / 1000 = 0.0316 M
• Mole of NaHCO₃ =?

Mole = Molarity x Volume

Mole of NaHCO₃ = 2 × 0.0316

Mole of NaHCO₃ = 0.0632 mole

How to determine the mole of CO₂

NaHCO₃ + HCl —> CO₂ + H₂O + NaCl

From the balanced equation above,

1 mole of NaHCO₃ reacted to produce 1 mole of CO₂.

Therefore,

0.0632 mole of NaHCO₃ will also react to produce 0.0632 mole of CO₂.

Thus, 0.0632 mole of CO₂ was obtained from the reaction

Learn more about stoichiometry:

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