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2 years ago

Read and solve the following probems

Mathematics

2 answers:

vichka [17]2 years ago

8 0

Answer:

8 Pizzas

Step-by-step explanation:

Data :

Sell = S = 57

Left = L = 7

Add them

57 + 7 = 64

64 is the total slices

As the vendor slice pizza into 8 pieces

Divide total slices with single pizza slices

64/8 = 8 pizzas

Fed [463]2 years ago

6 0

<h2><u><em>I8</em></u></h2><h2><u><em>The vendor sliced 8 whole p i z z as.</em></u></h2><h2><u><em></em></u></h2><h2><u><em>Step-by-step explanation:</em></u></h2><h2><u><em></em></u></h2><h2><u><em>Word Problem</em></u></h2><h2><u><em>The problem is asking for the total number of whole pizzas that the vendor sliced. There are two steps to find the answer.</em></u></h2><h2><u><em></em></u></h2><h2><u><em>Find the total number of slices of pizza by adding the number of slices sold and the number of slices left.</em></u></h2><h2><u><em>Find the total number of whole pizzas by dividing the total number of slices made into one whole pizza.</em></u></h2><h2><u><em>Given:</em></u></h2><h2><u><em></em></u></h2><h2><u><em>number of slices sold - 57</em></u></h2><h2><u><em></em></u></h2><h2><u><em>number of slices left - 7</em></u></h2><h2><u><em></em></u></h2><h2><u><em>number of slices into one whole pizza - 8</em></u></h2><h2><u><em></em></u></h2><h2><u><em>Solution:</em></u></h2><h2><u><em></em></u></h2><h2><u><em>Step 1: Add.</em></u></h2><h2><u><em></em></u></h2><h2><u><em>57 + 7 = 64</em></u></h2><h2><u><em></em></u></h2><h2><u><em>There were 64 slices of pizza.</em></u></h2><h2><u><em></em></u></h2><h2><u><em>Step 2: Divide.</em></u></h2><h2><u><em></em></u></h2><h2><u><em>64 ÷ 8 = 8</em></u></h2><h2><u><em></em></u></h2><h2><u><em>Final Answer:</em></u></h2><h2><u><em></em></u></h2><h2><u><em>The vendor sliced 8 whole pizzas.</em></u></h2>

<u><em>Thank you</em></u>

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1) Ten samples of a process measuring the number of returns per 100 receipts were taken for a local retail store.

densk [106]

Answer:

E) .0863

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

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Solution to the problem

For this case we can find the sample proportion for each observation with the following formula:

$\hat p = \frac{X}{n}$

Where X represent the number of returns and n =100 for each case since the standard value used. Using the last formula we got:

$p_1 = \frac{10}{100}=0.1$

$p_2 = \frac{9}{100}=0.09$

$p_3 = \frac{11}{100}=0.11$

$p_4 = \frac{7}{100}=0.07$

$p_5 = \frac{3}{100}=0.03$

$p_6 = \frac{12}{100}=0.12$

$p_7 = \frac{8}{100}=0.08$

$p_8 = \frac{4}{100}=0.04$

$p_9 = \frac{6}{100}=0.06$

$p_{10} = \frac{11}{100}=0.11$

And now witht those values we can find the sample mean of proportions with the following formula:

$hat p = \frac{\sum_{i=1}^n p_i}{n}= \frac{0.1+0.09+0.11+0.07+0.03+0.12+0.08+0.04+0.06+0.11}{10}=0.081$

And we can find the standard error with the following formula:

$SE= \sqrt{\frac{\hat p (1-\hat p)}{n}}=\sqrt{\frac{0.081(1-0.081)}{10}}=0.0863$

So then the best option on this case is given by:

E) .0863

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Step-by-step explanation:

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