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Gnoma [55]
3 years ago
10

There are 24 more students in the seventh grade class than the number g in the eighth grade class. The seventh grade class has 1

60 students. Write and solve an equation to find the number of students in the eighth grade class.
Mathematics
2 answers:
patriot [66]3 years ago
5 0

Answer:

y= 8th grade class,

y + 24 =160

subtract 24 from both sides

y=136

there are 136 students in the eight grade class

Step-by-step explanation:

Lubov Fominskaja [6]3 years ago
5 0

Answer:

136 students

Step-by-step explanation:

7th grade= 160 students

8th grade= g students

g= 160-24

g= 136 students

- I hope this helps have a great day!

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Point B has coordinates ​(​1,2​). The​ x-coordinate of point A is -8. The distance between point A and point B is 15 units. What
Xelga [282]

Answer:

The possible coordinates of point A are A_{1} (x,y) = (-8, 14) and A_{2} (x,y) = (-8, -10), respectively.

Step-by-step explanation:

From Analytical Geometry, we have the Equation of the Distance of a Line Segment between two points:

l_{AB} = \sqrt{(x_{B}-x_{A})^{2} + (y_{B}-y_{A})^{2}} (1)

Where:

l_{AB} - Length of the line segment AB.

x_{A}, x_{B} - x-coordinates of points A and B.

y_{A}, y_{B} - y-coordinates of points A and B.

If we know that l_{AB} = 15, x_{A} = -8, x_{B} = 1 and y_{B} = 2, then the possible coordinates of point A is:

\sqrt{(1+8)^{2}+(2-y_{A})^{2}} = 15

81 + (2-y_{A})^{2} = 225

(2-y_{A})^{2} = 144

2-y_{A} = \pm 12

There are two possible solutions:

1) 2-y_{A} = -12

y_{A} = 14

2) 2 - y_{A} = 12

y_{A} = -10

The possible coordinates of point A are A_{1} (x,y) = (-8, 14) and A_{2} (x,y) = (-8, -10), respectively.

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lozanna [386]

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Step-by-step explanation:

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kirill [66]

Answer:

The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

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99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 3.25

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The lower end of the interval is the sample mean subtracted by M. So it is 12,556 - 81 = 12,475 pounds

The upper end of the interval is the sample mean added to M. So it is 12,556 + 81 = 12,637 pounds.

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