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Triss [41]
2 years ago
13

The area of a rectangle is 5 x cubed + 19 x squared + 6 x minus 18 with length x + 3. Using synthetic division, what is the widt

h of the rectangle?.
SAT
1 answer:
Oxana [17]2 years ago
6 0

The width of the rectangle using synthetic division is; 5x² + 4x - 6

<h3>Synthetic division of Polynomials</h3>

We are given;

Area of rectangle = 5x³ + 19x² + 6x - 18

Length of rectangle = x + 3

We know that;

Width of rectangle = Area/length.

Using synthetic division, we have;

             <u>5x² + 4x - 6 </u>

  (x + 3) | 5x³ + 19x² + 6x - 18

            -  <u>5x³ + 15x²</u>

                           4x² + 6x

                         - <u>4x² + 12x</u>

                                   -6x - 18

                                   <u> -6x - 18</u>

                                            0

Thus, the width of the rectangle is 5x² + 4x - 6

Read more about polynomial synthetic division at; brainly.com/question/24323423

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