Since you did not provide the coordinates, I can't provide an exact answer.
However, I can tell you this; from the initial x-coordinate, move right 5 units. from the initial-y coordinate, move up 1 unit and you will have your answer.
Answer:
The result of the integral is
Step-by-step explanation:
We are given the following integral:
I am going to solve by substitution, using , so . So, we have
Which has the following result:
Going back to x, the result of the integral is
Answer:
√3
Step-by-step explanation:
To recall trigonometric ratios, there is a special acronym known as sohcahtoa which stands for
- <u>s</u>in(x)=<u>o</u>pposite/ <u>h</u>ypotenuse
- <u>c</u>os(x)=<u>a</u>djacent/<u>h</u>ypotenuse
- <u>t</u>an(x)=<u>o</u>pposite /<u>h</u>ypotenuse
<u>Finding</u><u> the</u><u> </u><u>angle</u><u> </u>
We are given that,
To find the angle , take inverse of sin of both sides,
with the help of unit circle,we acquire:
<u>Finding </u>
simply plug in the value of theta:
using unit circle,we get:
and we're done!
Answer:
The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
Suppose a sample of 292 tenth graders is drawn. Of the students sampled, 240 read above the eighth grade level.
So 292 - 240 = 52 read below or at eight grade level, and that
80% confidence level
So , z is the value of Z that has a pvalue of , so .
The lower limit of this interval is:
The upper limit of this interval is:
The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).