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3241004551 [841]
3 years ago
8

Christian read 1/4 book every 2/3 per week. How many books does he read per week

Mathematics
2 answers:
sergiy2304 [10]3 years ago
6 0

3/8th is your answer.

He reads 3/8th books per week.

Elina [12.6K]3 years ago
3 0

Answer:

Christian reads 3/8th of a book a week.

Step-by-step explanation:

In order to find this amount, we need to multiply both numbers by a factor that will get the weeks to equal 1. In order to get 2/3 to equal 1, we need to multiply by 3/2 (the reciprocal). Now knowing this, we can multiply the number of books by that same fraction to get the amount of books in one week.

1/4 * 3/2 = 3/8

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Step-by-step explanation:

5(1)/(5) = 1/(1)

5/5 = 1/1

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When finding the volume, we multiplied the 3 dimensions with degree of 1, 1 and 3 and got the binominal of degree 5. We summed up the degrees: 1 + 1 + 3 = 5.

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Simplify the expression<br> 4t + 10t
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5 0
3 years ago
A bin is constructed from sheet metal with a square base and 4 equal rectangular sides. if the bin is constructed from 48 square
kondaur [170]
This is a problem of maxima and minima using derivative.

In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

V = length x width x height

That is:

V = xxy = x^{2}y

We also know that the <span>bin is constructed from 48 square feet of sheet metal, s</span>o:

Surface area of the square base = x^{2}

Surface area of the rectangular sides = 4xy

Therefore, the total area of the cube is:

A = 48 ft^{2} =  x^{2} + 4xy

Isolating the variable y in terms of x:

y =  \frac{48- x^{2} }{4x}

Substituting this value in V:

V =  x^{2}( \frac{48- x^{2} }{x}) = 48x- x^{3}

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

\frac{dv}{dx} = 48-3x^{2} =0

Solving for x:

x =  \sqrt{\frac{48}{3}} =  \sqrt{16} = 4

Solving for y:

y =  \frac{48- 4^{2} }{(4)(4)} = 2

Then, <span>the dimensions of the largest volume of such a bin is:
</span>
Length = 4 ft
Width =  4 ft
Height = 2 ft

And its volume is:

V = (4^{2} )(2) = 32 ft^{3}

8 0
3 years ago
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